How many total electron will fit in the 1st energy level

Given the following reaction: 3D(g) + E(g) + 2F(g) → 5G(g) + 4H(g)

evablogger [386]

Answer:

Explanation:

Hello,

The law of mass action, allows us to know the required amounts, thus, for this chemical reaction it is:

$\frac{1}{-3} \frac{d[D]}{dt} =\frac{1}{-1} \frac{d[E]}{dt} =\frac{1}{-2} \frac{d[F]}{dt} =\frac{1}{5} \frac{d[G]}{dt} =\frac{1}{4} \frac{d[H]}{dt}$

Now, we answer:

(a)

$\frac{d[H]}{dt}=4*\frac{1}{-3} *(-0.12M/s)=0.16M/s$

(b)

$\frac{d[E]}{dt}=-1*\frac{1}{5} *(0.2M/s)=-0.04M/s$

(c) Since no initial data is specified, we could establish the rate of the reaction as based of the law of mass action:

$r=\frac{1}{-3} \frac{d[D]}{dt} =\frac{1}{-1} \frac{d[E]}{dt} =\frac{1}{-2} \frac{d[F]}{dt} =\frac{1}{5} \frac{d[G]}{dt} =\frac{1}{4} \frac{d[H]}{dt}$

Thus, any of the available expressions are suitable to quantify the rate of the reaction.

Best regards.

4 0

3 years ago

One of the intermediates in the synthesis of glycine from ammonia, carbon dioxide, and methane is aminoacetonitrile, C2H4N2.

mart [117]

Answer:

You could expect 3.48 grams of C₂H₄N₂

Explanation:

You must start by stating the chemical equation for the reaction of ammonia, carbon dioxide, and methane to produce aminoaceto nitrile.

1. Word equation:

Ammonia + Carbon dioxide + Methane → Aminoacetonitrile + Water

2. Balanced chemical equation:

$8NH_3+5CO_2+3CH_4\rightarrow 4C_2H_4N_2 +10H_2O$

3. Convert the mass of each reactant into number of moles:

Formula:

Number of moles = mass in grams/molar mass

2.11g NH₃

Number of moles = 2.11g / 17.03g/mol = 0.124 mol NH₃

14.9g CO₂

Number of moles = 14.9g/44.01g/mol = 0.339 mol CO₂

1.75g CH₄

Number of moles = 1.75g/16.04g/mol = 0.109 mol CH₄

4. Theoretical mol ratio

From the balanced chemical equation, using the coefficientes:

$8molNH_3:5molCO_2:3molCH_4:4molC_2H_4N_2:10molH_2O$

5. Limiting reagent

The available amounts of the reactants are:

0.124 mol NH₃

0.339 mol CO₂

0.109 mol CH₄

Fom the theoretical mole ration, to react with 0.124 mol of NH₃ you would need:

0.124molNH₃ × (5molCO₂/8molNH₃) = 0.0775 mol CO₂

Since there are 0.339 moles available, this is in excess.

0.124molNH₃ × (3molCH₄/8molNH₃) = 0.0465mol CO₂

Since there are 0.109 moles available, this is in excess too.

Hence, the limiting reagent is NH₃.

6. Yield

Use the theoretical ratio:

0.124molNH₃ × (4molC₂H₄N₂ / 8molNH₃) = 0.0620 mol C₂H₄N₂

Convert to grams:

Mass = number of moles × molar mass

0..0620 mol × 56.068g/mol = 3.48 g of C₂H₄N₂ ← answer

4 0

3 years ago

What element is in the 3 rd period and 7th family

aleksley [76]

Pokémon is it that's the anwser

4 0

3 years ago

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Which diagram represents an electrically neutral atom?

Rom4ik [11]

Answer:

D

Explanation:

I hope this right, I'm sorry if it's not.

For an atom to be neutral, it has to have the same amount of protons and electrons. Because protons and electrons have opposite charges, when there is an equal amount of them they balance each other out

5 0

3 years ago

Read 2 more answers

Does anyone know what the formula would be for Rhenium V Biphosphate?

Georgia [21]

Answer:Re3(PO4)2 I think I'm wrong

Explanation:

8 0

2 years ago