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kompoz [17]
3 years ago
12

Predict whether a reaction occurs, and write balanced complete and net ionic equations:(a) Iron (III) chloride (aq) + cesium pho

sphate (aq) →(b) Sodium hydroxide (aq) + cadmium nitrate (aq) →(c) Magnesium bromide (aq) + potassium acetate (aq) →(d) Silver sulfate (aq) + barium chloride (aq) →(e) Sodium sulfate (aq) + strontium nitrate (aq) →
Chemistry
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer : The balanced complete and net ionic equations are written below.

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(a) The balanced molecular equation will be,

FeCl_3(aq)+Cs_3PO_4(aq)\rightarrow 3CsCl(aq)+FePO_4(s)

The complete ionic equation in separated aqueous solution will be,

Fe^{3+}(aq)+3Cl^{-}(aq)+3Cs^{+}(aq)+PO_4^{3-}(aq)\rightarrow 3Cs^{+}(aq)+3Cl^{-}(aq)+FePO_4(s)

In this equation the species present are, 3Cl^{-}\text{ and }Cs^{+} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Fe^{3+}(aq)+PO_4^{3-}(aq)\rightarrow FePO_4(s)

(b) The balanced molecular equation will be,

2NaOH(aq)+Cd(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+Cd(OH)_2(s)

The complete ionic equation in separated aqueous solution will be,

2Na^{+}(aq)+2OH^{-}(aq)+Cd^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+Cd(OH)_2(s)

In this equation the species present are, Na^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Cd^{2+}(aq)+2OH^{-}(aq)\rightarrow Cd(OH)_2(s)

(c) The balanced molecular equation will be,

MgBr_2(aq)+2CH_3COOK(aq)\rightarrow (CH_3COO)_2Mg(aq)+2KBr(aq)

The complete ionic equation in separated aqueous solution will be,

Mg^{2+}(aq)+2Br^{-}(aq)+2K^{+}(aq)+2CH_3COO^{-}(aq)\rightarrow Mg^{2+}(aq)+2CH_3COO^{-}(aq)+2Br^{-}(aq)+2K^{+}(aq)

In this equation all the species are the spectator ions.

Thus, there is no net ionic equation.

(d) The balanced molecular equation will be,

Ag_2SO_4(aq)+BaCl_2(aq)\rightarrow 2AgCl(s)+BaSO_4(s)

The complete ionic equation in separated aqueous solution will be,

2Ag^{+}(aq)+SO_4^{2-}(aq)+Ba^{2+}(aq)+2Cl^{-}(aq)\rightarrow 2AgCl(s)+BaSO_4(s)

In this equation no species are the spectator ions.

Thus, there is no net ionic equation.

(e) The balanced molecular equation will be,

Na_2SO_4(aq)+Sr(NO_3)_2(aq)\rightarrow 2NaNO_3(aq)+SrSO_4(s)

The complete ionic equation in separated aqueous solution will be,

2Na^{+}(aq)+SO_4^{2-}(aq)+Sr^{2+}(aq)+2NO_3^{-}(aq)\rightarrow 2Na^{+}(aq)+2NO_3^{-}(aq)+SrSO_4(s)

In this equation the species present are, Na^{+}\text{ and }NO_3^{-} are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

Sr^{2+}(aq)+SO_4^{2-}(aq)\rightarrow SrSO_4(s)

You might be interested in
Write balanced chemical equations for the following reactions.
VLD [36.1K]

❃ The following points should be kept in mind to write and balance a chemical equation :

Step 1 : Write the molecular formula of all the reactants and products correctly.

Step 2 : Separate reactants and products by a sign of arrow. If reactants or products are more than one, connect them by a sign of a plus.

Step 3 : Balance the atoms of O and H at last [ The atoms used at many places in an equation should be balanced at last ]. For balancing , the number should be added as coefficient i.e in the front of the molecules.

[ Remember those substance that take part in a chemical reaction are called reactants. Likewise , those substances which are formed after a chemical reaction are called products ]

\large{ \tt{❁ \: LET'S \: GET \: STARTED}} :

1. Carbon disulfide + Oxygen gas gives carbon dioxide + Sulfur dioxide.

Step 1 : The molecular formula of carbon disulfide is CS₂ , molecular formula of Oxygen gas is 0₂ [ Since oxygen is a diatomic element ] molecular formula of carbon dioxide is CO₂ and molecular formula of sulfur dioxide is SO₂.

Step 2 : CS₂ + O₂ ⟶ CO₂ + SO₂

Step 3 : In the reactant side , there is two ' S ' but on the other side , there is one ' S '. So , add 2 as a coefficient before S on the product side. Now , There are two ' O ' in the reactant side but six ' O ' in the product side. So , add 3 as a coefficient before O on the reactant side. Now , there are equal atom of C , S and O on both sides

i.e CS₂ + 3O₂ ⟶ CO₂ + 2SO₂

Answer : \boxed{ \tt{CS₂ + 3O₂ ⟶ CO₂ + 2SO₂}}

-----------------------------------------

2. Silver + nitric acid gives silver nitrate + nitrogen dioxide + water

Step 1 : The molecular formula of Silver is Ag, molecular formula of nitric acid is HNO₃ , molecular formula of Silver nitrate is Ag ( No₃ ) , molecular formula of nitrogen dioxide is NO₂ and molecular formula of water is H₂O.

Step 2 : Ag + HNO₃ ⟶ Ag ( NO₃ ) + NO₂ + H₂O

Step 3 : In the reactant side , There is one ' H ' but on the other side , there are two ' H '. Now add 2 before H on the reactant side. There are equal atom of ' Ag ' , ' H ' , ' N ' , and ' O '.

i.e Ag + 2HNO₃ ⟶ Ag ( NO₃ ) + NO₂ + H₂O

Answer : \boxed{ \tt{Ag + 2HNO₃ ⟶ Ag ( NO₃ ) + NO₂ + H₂O }}

  • Yay! We're done ! :)

- The last step is a bit more confusing I guess. So , which balancing , count the atoms in following ways :

  • The number written at the right lower corner of an atom is counted for that atom only. For example : In MgSO₄ , there are one ' Mg ' , one ' S ' and four ' O '

  • The number written at the right lower corner of a bracket is for all the atoms enclosed in the bracket. For example : In Al₂ ( SiO₃ ) has two Al , three ' S ' and nine ' O '.

  • The coefficient number is for all the atoms of the molecule. For example , in 2 Al ₂( SiO₃ )₃ , there are four ' Al ' , six ' Al ' and eighteen ' O '.

- Hope this helps! :)

4 0
3 years ago
Read 2 more answers
an electron in the 3rd shell of an Aluminium atom moves to the first shell in a bombardment process. Calculate the frequency of
Liula [17]

Following the quantic theory, the energy of a photon equals the radiation frequency multiplied by the universal constant. ν = 2.923x10¹⁵ Hz. E = 3.09x10¹⁵Hz.

<h3>What is quantum mechanic?</h3>

It is the branch of physics that studies objects and forces at a very low scale, at atoms, subatoms, and particles levels.

Quantum mechanics states that the elemental particles that constitute matter -electrons, neutrons, protons- have the properties of a wave and a particle.

It emerges from the quantic theory exposed by Max Planck (1922), in which he affirmed that light propagates in energy packages or photons.

He discovered the Universal Planck constant, h, used to calculate the energy of a photon.

He stated that the energy of a photon (E) equals the radiation frequency (ν) multiplied by the universal constant (h).

E = νh

In the exposed example, we need to calculate the energy required to change from the 3rd shell to the first shell.

To do it, we should know that the energy in a level (Eₙ) equals the energy associated to an electron in the most inferior energy level (E₁) divided by the square of the shell number (n²).

Eₙ = E₁ / n²

E₁ is a constant. We can express it in <em>Joules </em>or <em>electroVolts </em>

  • E₁ = -2.18x10⁻¹⁸ J
  • E₁ = -13.6 eV

So, let us calculate the energy at level 1 and 3

Eₙ = E₁ / n²

  • E₁ =  -2.18x10⁻¹⁸ J / 1² =<u>  -2.18x10⁻¹⁸</u><u> J</u>

        E₁ =  -13.6 eV / 1² =<u>  -13.6 </u><u>eV</u>

  • E₃ =  -2.18x10⁻¹⁸ J / 3² =  -2.18x10⁻¹⁸ J / 9 =<u> - 2.42x10⁻¹⁹ </u><u>J</u>

        E₃ =  -13.6 eV / 3² =  -13.6 eV / 9 = <u>- 1.51 </u><u>eV</u>

The change of energy can be calculated in two ways,

<u>Option 1</u>

ΔE = E₁ - E₃ = 2.18x10⁻¹⁸ - 2.42x10⁻¹⁹ =<u> 1.93x10⁻¹⁸</u><u>J</u>

ΔE = E₁ - E₃ = 13.6 - 1.51 = <u>12.09 </u><u>eV</u>

<u>Option 2</u>

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE =-13.6 eV (1/nf² - 1/ni²)

Where nf is the final level and ni is the initial level. When the electron passes from its initial level to its final level it is called electronic transition.

  • ni = 3
  • nf = 1

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE = -2.18x10⁻¹⁸ J (1/1² - 1/3²)

ΔE = -2.18x10⁻¹⁸ J (1 - 0.111)

ΔE = -2.18x10⁻¹⁸ J (0.888)

<u>ΔE</u><u> = - 1.937x10⁻¹⁸ </u><u>J</u>

or

ΔE = -13.6 eV  (1/nf² - 1/ni²)

ΔE = -13.6 eV  (1/1² - 1/3²)

ΔE = -13.6 eV  (1 - 0.111)

ΔE = -13.6 eV  (0.888)

<u>ΔE</u><u> = -12.08</u><u> eV</u>

This is the energy required for the electron to go from n= 3 to n = 1. The negative sign (-) means energy (as light or photons) released or emitted.

<u />

If we want to express the result in Hz, we just need to make a conversion.

1Hz ⇔ 6.626x10⁻³⁴J ⇔ 4.136x10¹⁵ eV.

The energy required for the electron to go from n= 3 to n = 1 is <u>3.09x10¹⁵ </u><u>Hz</u><u>.</u>

Now, we need to calculate the frequency, ν. This is, how many times the wave oscillates back and foward per second.

To do it, we will use the universal Planck constant, h, and the absolute value of the energy, E.

ν = E/h = 1.937x10⁻¹⁸ J / 6.626x10⁻³⁴ Js = 2.923x10¹⁵ 1/s =  <u>2.923x10¹⁵ Hz</u>.

<u>Answer</u>:

  • Frequency, ν = E/h = <u>2.923x10¹⁵ </u><u>Hz</u>.
  • Energy, E = <u>3.09x10¹⁵ </u><u>Hz</u><u>.</u>

You can learn more about quantum mechanic at

brainly.com/question/11855107

brainly.com/question/23780112

brainly.com/question/11852353

5 0
2 years ago
Which solution will have the highest ph? the ka of hclo is 3.8 × 10−8.
Ilya [14]
The one with the highest pH would be a solution with 100 mL of water and also 20 mL of 0.1 M NaOH is added. Solutions without buffers would have the highest pH since the resistance to change is very low. Hope this answers the question.
3 0
3 years ago
In an experiment, the same mass of magnesium metal reacted with the same amount of two different acids. the acid used in reactio
denpristay [2]

The mole ratio of the reaction shows that equal volumes of hydrogen gas will be produced by the two reactions.

<h3>What is the mole ratio of a reaction?</h3>

The mole ratio of a reaction is the ratio in which the reactants and products of a given reaction occur for the reaction to proceed to completion.

The mole ratio of a reaction is also known as the stoichiometry of the reaction.

The equation of the two reactions are given below:

Mg + 2HCl \rightarrow MgCl_2 + H_2

Mg + 2CH_3COOH \rightarrow (CH_3COO)_2Mg + H_2 \\

From the equation of the reaction reaction, an equal volume of hydrogen gas will be produced by the two reactions.

Therefore, the mole ratio of the reaction shows that equal volumes of hydrogen gas will be produced by the two reactions.

Learn more about mole ratio at: brainly.com/question/19099163

#SPJ1

6 0
2 years ago
Which one is the answer?
nadya68 [22]
I would go with C because that seems like the best answer choice
3 0
3 years ago
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