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Veronika [31]
3 years ago
12

Need a lil help here

Chemistry
2 answers:
Step2247 [10]3 years ago
7 0
OKKKKKKKKKKKKKKKKKKKKKK

harina [27]3 years ago
5 0

Answer:

im not the realest igga is the anwer

Explanation:

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If I raise the Celsius scale by 15 degrees, how<br> much will I be raising it in the Kelvin Scale?
Mariana [72]

Answer:

If the change is +15 degrees Celsius, the change is +15 Kelvin (note that it's not degrees Kelvin, just simply Kelvin). You can use the conversion, which is 273.15 Kelvin = zero degrees Celsius. Since it's a relative scale, 10 C = 274.15 K, and 20 C = 275.15 and so forth.

6 0
3 years ago
Un isótopo de un elemento metálico tiene un número de masa de 65 y tiene 35 neutrones en su núcleo. El catión derivado de dicho
poizon [28]
According to Data,
                             Mass Number  =  65

                             # of Neutrons  =  35

As we know,
                             Mass Number  =  # of protons + # of Neutrons
Solving for # of protons,
                                # of protons  =  Mass Number - # of Neutrons
Putting values,
                                # of Protons  =  65 -35

                                # of protons  =  30
As, 

# of protons is the atomic number, so element with atomic number 30 is Zinc.

The cation derived from it has 28 electrons,
So, Zinc having 30 electron will be left with two extra protons, and each proton has +1 charge.

Result:
                                                    Zn
²⁺
8 0
3 years ago
What is an energy conserved system ?
grin007 [14]

Answer: In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.

Explanation:

internet

6 0
3 years ago
For each of the following balanced chemical equations, calculate how many moles and how many grams of each product would be prod
natima [27]

Answer:

(a)

Moles of ammonium chloride = 0.5 mole

Mass of ammonium chloride formed = 26.7455 g

(b)

Mole of CS_2 = 0.125 mole

Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g

Mole of H_2S = 0.25 mole

Mass = Moles * Molar mass = 0.25 * 34.1 g = 8.525 g

Explanation:

(a)

For the first reaction:-

NH_3_{(g)}+HCl_{(g)}\rightarrow NH_4Cl_{(s)}

The mole ratio of the reactants = 1 : 1

0.5 moles of ammonia react with 0.5 moles of hydrochloric gas to give 0.5 moles of ammonium chloride

So, <u>Moles of ammonium chloride formed = 0.5 moles</u>

Molar mass of ammonium chloride = 53.491 g/mol

<u>Mass = Moles * Molar mass = 0.5 * 53.491 g = 26.7455 g</u>

(b)

For the first reaction:-

CH_4_{(g)}+4S_{(s)}\rightarrow CS_2_{(l)}+2H_2S_{(g)}

The mole ratio of the reactants = 1 : 4

It means

0.5 moles of methane react with 2.0 moles of sulfur to give 0.5 moles of Carbon disulfide and 1.0 moles of hydrogen sulfide gas.

But available moles of S = 0.5 moles

Limiting reagent is the one which is present in small amount. Thus, S is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

4 moles of S produces 1 mole of CS_2

Thus,

0.5 moles of S produces \frac{1}{4}\times 0.5 mole of CS_2

<u>Mole of CS_2 = 0.125 mole</u>

Molar mass of CS_2 = 76.139 g/mol

<u>Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g</u>

4 moles of S produces 2 moles of H_2S

Thus,

0.5 moles of S produces \frac{2}{4}\times 0.5 mole of H_2S

<u>Mole of H_2S = 0.25 mole</u>

Molar mass of H_2S = 34.1 g/mol

<u>Mass = Moles * Molar mass = 0.25 * 34.1 g = 8.525 g</u>

<u></u>

7 0
3 years ago
. The electron affinity for an oxygen atom is negative. What statement is probably true regarding
kramer
The best and most correct answer among the choices provided by your question is the second choice or letter B.

<span>Regarding the second electron affinity for an oxygen, i. e., the electron affinity for O-, it is much larger and negative.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
7 0
3 years ago
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