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blagie [28]
3 years ago
5

You are a scientist trying to develop a technology that can be used to power wrist watches. Which type of electromagnetic wave w

ould be most useful to investigate?
Gamma rays, because they are powerful and safe.
Infrared waves, because they do not produce heat and have high energy.
Ultraviolet waves, because they have moderate energy and are abundant.
Microwaves, because they are powerful and available.
Physics
2 answers:
serg [7]3 years ago
5 0

Well I don't know.  Let's examine the choices one at a time:

-- Gamma rays ... NO, they are NOT safe.

-- Infrared waves ... NO, they DO produce heat.

-- Ultraviolet waves ... Maybe.  They have plenty of energy, and they're abundant in sunlight.  But unrestricted exposure to them is somewhat dangerous.  

-- Microwaves ... Maybe.  They can be generated with plenty of energy, with inexpensive devices. (They're even used, in most homes, to warm up leftover meatloaf.)  They're safe at moderate power levels, and they're actually all over the place right now.

I think my personal choice is microwaves.

Salsk061 [2.6K]3 years ago
3 0
Microwave because they are powerful and available can be d answer
You might be interested in
A car travels 400 km in 5 hours. what is the average speed of the car (in km/hr) ?
PtichkaEL [24]
Distance travel = 400km
Time it took to travel 400km = 5 hr

Average speed = (distance travel)/(Time for that travel)

s = 400km/5h = 80km/hr

The average speed is 80km/hr.
3 0
3 years ago
If a wave y(x, t) (6.0 mm) sin(kx (600 rad/s)t f) travels along a string, how much time does any given point on the string take
kipiarov [429]

Answer:

t₁ - t₂ = 0.0011 s

Explanation:

given,

y(x, t) = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

now,

y m = 6 mm        ω = 600 rad/s

y₁ = + 2.0 mm    y₂ = -2 .0 mm

now,

2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

-2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

so,

kx + (600 rad/s)t₁ + Φ = \dfrac{\pi}{180}sin^{-1}(\dfrac{1}{3})......(1)

we have multiplied with π/180 to convert angle into radians

kx + (600 rad/s)t₂ + Φ = \dfrac{\pi}{180}sin^{-1}(-\dfrac{1}{3})......(2)

subtracting both the equation (1)-(2)

600(t₁-t₂) =  \dfrac{2\pi}{180}sin^{-1}(\dfrac{1}{3})

now,

    t₁ - t₂ = 0.0011 s

time does any given point on the string take to move between displacements is equal to 0.0011 s

3 0
3 years ago
The Coulomb force between two charges q1 and q2 at separation r in air is F. If half of the separation is filled with medium of
vodomira [7]

Answer:

The new Coulomb force is q₁q₂/9πε₀r²

Explanation

The coulomb force between the two charges q₁ and q₂ at a distance r in air is given by F = q₁q₂/4πε₀r².

Now, let us assume the material of dielectric constant κ = 9 is placed between them on the side of the q₁ charge. The value of its effective charge is now q₃ = q₁/κ at a distance of d = r/2 from the q₂ charge.

Since we have air between q₂ and q₃, the coulomb force between them is

F' = q₂q₃/4πε₀d²

= q₂(q₁/κ)/4πε₀(r/2)²

=  4q₂q₁/κ4πε₀r²

= 4/κ(q₂q₁/4πε₀r²)

= 4/9 × (q₂q₁/4πε₀r²)

= q₁q₂/9πε₀r²

So, the new Coulomb force is q₁q₂/9πε₀r²

3 0
4 years ago
A small sphere with mass 1.5g hangs by a thread between two parallel vertical plates 5cm apart. The plates are insulating and ha
kondaur [170]

The tralational equilibrium condition allows finding that the electric potential is   V = 4.8 10¹¹ V

Given parameter

  • The mass m = 1.5 g = 1.15 10-3 kg
  • The charge on the sphere q = 8.9 10-16 C
  • Plate spacing d = 5 cm = 5.00 10-2 m

To find

  • The potential difference

Newton's second law states that the force is proportional to the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it establishes the condition for the equilibrium of the bodies

          ∑ F = 0

Where the bold indicate vector and F is the force

To use this equation we must fix a reference system with respect to which to carry out the decomposition and measurements of the forces; let's fix a system with the horizontal x axis and the vertical y axis, in the attachment I could see a free body diagram.

x- axis

     Fe - Tₓ = 0

     Fe = Tₓ

y-axis

     T_y - W = 0

     W = T_y

     mg = T_y

The electric force is

      Fe = q E = q V / d

let's use trigonometry to decompose the stress

     cos 30 =  T_y / T

     sin 30 = Tₓ / T

      T_y = T cos 30

      Tₓ = T sin 30

We substitute

        q V / d = T sin 30

        mg = T cos 30

It's solve the system of equations

         \frac{q \ V}{d \ m g} = tan 30

         V = \frac{d \ mg }{ q}\ tan \  30

It's calculate

         V = \frac{5.00 \ 10^{-2} 1.5 \ 10^{-3} \ 9.8}{ 8.9 10^{-16} } \ tan \ 30

         V = 4.768 10¹¹ V

In conclusion, using the equilibrium condition, we could find that the electric potential is V = 4.8 10¹¹ V

Learn more about equilibrium condition here:

brainly.com/question/1967702

7 0
3 years ago
10.20) Perform the following conversions: (a) 0.912 atm to torr,(b) 0.685 bar to kilopascals, (c) 655 mm Hg to atmospheres,(d) 1
masha68 [24]

Answer:

(a) 693.12 torr

(b) 68.5 kilopascals

(c) 0.862 atmosphere

(d) 1.306 atmospheres

(e) 36.74 psi

Explanation:

(a) 0.912 atm = 0.912 atm × 760 torr/1 atm = 693.12 torr

(b) 0.685 bar = 0.685 bar × 100 kPa/1 bar = 68.5 kPa

(c) 655 mmHg = 655 mmHg × 1 atm/760 mmHg = 0.862 atm

(d) 1.323×10^5 Pa = 1.323×10^5 Pa × 1 atm/1.01325×10^5 Pa = 1.306 atm

(e) 2.50 atm = 2.50 atm × 14.696 psi/1 atm = 36.74 psi

5 0
3 years ago
Read 2 more answers
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