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blagie [28]
3 years ago
5

You are a scientist trying to develop a technology that can be used to power wrist watches. Which type of electromagnetic wave w

ould be most useful to investigate?
Gamma rays, because they are powerful and safe.
Infrared waves, because they do not produce heat and have high energy.
Ultraviolet waves, because they have moderate energy and are abundant.
Microwaves, because they are powerful and available.
Physics
2 answers:
serg [7]3 years ago
5 0

Well I don't know.  Let's examine the choices one at a time:

-- Gamma rays ... NO, they are NOT safe.

-- Infrared waves ... NO, they DO produce heat.

-- Ultraviolet waves ... Maybe.  They have plenty of energy, and they're abundant in sunlight.  But unrestricted exposure to them is somewhat dangerous.  

-- Microwaves ... Maybe.  They can be generated with plenty of energy, with inexpensive devices. (They're even used, in most homes, to warm up leftover meatloaf.)  They're safe at moderate power levels, and they're actually all over the place right now.

I think my personal choice is microwaves.

Salsk061 [2.6K]3 years ago
3 0
Microwave because they are powerful and available can be d answer
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Mila [183]

Answer:

a. Picture attached

b. V, X

c. t=0.12 s

d. It makes sense cosidering that a normal heart beat rate is between 60 and 100 beats per minute (bpm).

Explanation:

First we have to identify the unknown of this problem:

a: acceleration\\t: time

Considering the characteristics of the problem and that distance and velocity are specified, the acceleration is constant, for that reason we use the equations of uniformly accelerated motion as follows:

v=v_{0}+at\\ x=x_{0}+ v_{0}+\frac{1}{2}at^{2}

If we reorganize the equations, considering that x_{0} and v_{0} are zero because motion starts from rest , we have:

a=\frac{v}{t} \\x=\frac{1}{2}at^{2}  =\frac{1}{2}\frac{v}{t} t^{2}=\frac{1}{2} vt\\t=\frac{2x}{v} \\t=\frac{2*1.80cm}{30.0\frac{cm}{s} } \\t=0.12 s

Finally, the analysis of the result leaves us to understand why the normal heart beat rate varies between 60 and 100 bpm.

6 0
3 years ago
If you sit on a skateboard and push against a brick wall, what would happen? Why do you think this?
Troyanec [42]

Answer:

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Two wheels have the same mass and radius of 4.1 kg and 0.37 m, respectively. one has (a) the shape of a hoop and the other (b) t
snow_lady [41]
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3 years ago
What characteristics determine how easily two substances change temperature
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3 years ago
A circular loop of wire 75 mm in radius carries a current of 113 A. Find the (a) magnetic field strength and (b) energy density
Roman55 [17]

The magnetic field strength is 9.47 ×10⁻⁴ T

The energy density at the center of the loop is 0.36 J/m³

<h3>Calculating Magnetic field strength & Energy density </h3>

From the question, we are to find the magnetic field strength

The magnetic field strength of a loop can be calculated by using the formula,

B = \frac{\mu_{0} I}{2R}

Where  B is the magnetic field strength

\mu_{0} is the permeability of free space (\mu_{0}=4\pi \times 10^{-7} \ N/A^{2})

I is the current

and R is the radius

From the give information,

R = 75 \ mm= 75 \times 10^{-3} \ m

and I = 113 \ A

Putting the parameters into the formula, we get

B = \frac{4\pi \times 10^{-7} \times 113}{2 \times 75 \times 10^{-3} }

B = 9.47 \times 10^{-4} \ T

Hence, the magnetic field strength is 9.47 ×10⁻⁴ T

Now, for the energy density

Energy density can be calculated by using the formula,

u_{B}  = \frac{B^{2} }{2\mu_{0} }

Where u_{B} is the energy density

Then,

u_{B}= \frac{(9.47\times 10^{-4} )^{2} }{2 \times 4\pi \times 10^{-7} }

u_{B} = 0.36 \ J/m^{3}

Hence, the energy density at the center of the loop is 0.36 J/m³

Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557

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