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blagie [28]
3 years ago
5

You are a scientist trying to develop a technology that can be used to power wrist watches. Which type of electromagnetic wave w

ould be most useful to investigate?
Gamma rays, because they are powerful and safe.
Infrared waves, because they do not produce heat and have high energy.
Ultraviolet waves, because they have moderate energy and are abundant.
Microwaves, because they are powerful and available.
Physics
2 answers:
serg [7]3 years ago
5 0

Well I don't know.  Let's examine the choices one at a time:

-- Gamma rays ... NO, they are NOT safe.

-- Infrared waves ... NO, they DO produce heat.

-- Ultraviolet waves ... Maybe.  They have plenty of energy, and they're abundant in sunlight.  But unrestricted exposure to them is somewhat dangerous.  

-- Microwaves ... Maybe.  They can be generated with plenty of energy, with inexpensive devices. (They're even used, in most homes, to warm up leftover meatloaf.)  They're safe at moderate power levels, and they're actually all over the place right now.

I think my personal choice is microwaves.

Salsk061 [2.6K]3 years ago
3 0
Microwave because they are powerful and available can be d answer
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The bearing of lines A and B are 16° 10` and 332° 18`, the value of the included angle BOA is:_______
slega [8]

Answer:

D. 43° 52`  

Explanation:

A bearing is an angle, measured clockwise from the north direction. When solving a bearing problem, it is good to represent the bearings in the given question with diagram.

The diagrammatically representation of the bearing of lines A and B, 16° 10` and 332° 18` respectively given in the question is shown in the figure attached.

At Point A, we will calculate angle ∠BAO.

Calculating the angle ∠BAO

∠BAO = 90° - 16° 10`

          = 73° 50`

At Point B, we will calculate angle ∠ABO.

Calculating the angle ∠ABO

∠ABO = 332° 18` - 270° 0`

          = 62° 18`

At Point O, we will calculate the include angle ∠BOA.

Calculating the angle ∠BOA

∠BAO + ∠ABO + ∠BOA = 180°  (sum of angles in a triangle)

73° 50` + 62° 18` + ∠BOA = 180°

136° 8` + ∠BOA = 180°

∠BOA = 180° - 136° 8`

∠BOA = 43° 52`

The value of the included angle BOA is 43° 52

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If an equivalent (eq) is defined as a mole of charge, what is the concentration of ca2 in blood plasma in eq if its concentratio
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The concentration of ca2 in blood plasma is comparable if it is 0.0080, according to the supplied statement.

<h3>How do you quantify concentration?</h3>

Subtract the solute's mass from the total volume of the mixture. Calculate C = m/V, where m is the solute's mass and V seems to be the total volume of such solution. Divide the figures you found for mass and volume to find approximate concentration for your solution.

<h3>What is the definition of concentration in the solution?</h3>

A solution's concentration is a measure of how much solute has been dissolved in a specific amount of the solvent or solution. A concentrated solution contains a significant amount or dissolved solute. A dilute solution is one with a little amount of dissolved solute.

<h3>According to the given data:</h3>

The equivalent weight of detail is the mass that combines with someone or displaces 1.008 grams of molecular hydrogen, or eight.

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Those figures are the atomic weight divided by that of the normal valence, which is sixteen in the case of oxygen.

One Ca2+ ion has a charge of +2.Calcium ion concentration:

= 0.0040M ⇒ Ca ​​​​2+ Concentration in blood plasma

= 0.0040 × 2⇒ 0.0080 equivalent Ca2

To know more about concentration visit: brainly.com/question/10725862

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