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3 years ago

A ski jumper travels down a slope and

Physics

1 answer:

AleksandrR [38]3 years ago

5 0

Answer:

304.86 metres

Explanation:

The x and y cordinates are $dcos\theta$ and $dsin\theta$ respectively

The horizontal distance travelled, $x=v_{ox}t=dcos\theta$

Making t the subject, $t=\frac{dcos\theta}{v_{ox}}$

Since $y=0.5gt^2=dsin\theta$ , we substitute t with the above and obtain

$0.5g(\frac{dcos\theta}{v_{ox}})^2=dsin\theta$

Making d the subject we obtain

$d=\frac{2v_{ox}^2sin\theta}{gcos^2\theta}$

$d=\frac{2*30^2sin48}{9.8cos^248}$

d=304.8584

d=304.86m

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ArbitrLikvidat [17]

Answer:

The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x $10^{-4}$ N/C

Explanation:

given information,

kinetic energy, KE = 3.25 x $10^{-15}$ J

proton's mass, m = 1.673 x $10^{-27}$ kg

charge, q = 1.602 x $10^{-19}$ C

distance, d = 2 m

to find the electric field that will stop the proton, we can use the following equation:

E = F/q

= (KE/d) / q , KE = Fd --> F = KE/d

= KE/qd

= (3.25 x $10^{-15}$ J) / (1.602 x $10^{-19}$ C)(2 m)

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3 years ago

A grocery cart with a mass of 15 kg is pushed at constant speed along an aisle by a force fp = 12 n which acts at an angle of 17

Korolek [52]

Given:

Mass of cart: 15kg

Aisle length = 14m

Angle = 17° below the horizontal

Force fp = 12 N

So, the solution would be like this for this specific problem:

1) W(by applied force) = F(applied) x s x cosθ 
=>W(a) = 12 x 14 x cos17* = 160.66 J 

2) By F(net) = F(applied) - F(friction) 
=>As v = constant => a = 0 => F(net) = 0
=>F(applied) = F(friction)
=>W(friction) = -F(friction) x s
=>W(friction) = -F(applied) x s
=>W(f) = -12 x 14 x cos17* = -160.56 J 

3) 0, as the displacement is perpendicular to Force 

4) 0, as the displacement is perpendicular to Force

To add, the force that is applied to an object by a person or another object is called the applied force.

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3 years ago

A motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travel

Misha Larkins [42]

Explanation:

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$x = vt + \frac{1}{2} a {t}^{2}$

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$x = 3(1.8) + \frac{1}{2} (9.3) {1.8}^{2}$

through simple algebra we get

$x = 20.466$

where this is the distance traveled in meters.

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3 years ago

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Katyanochek1 [597]

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3 years ago

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The correct answer is this one:

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3 years ago