Question

Turner’s treadmill starts with a velocity of

Answer 1

33 60 

--- 

1980 33*60sec = 1980 sec for comparison

Answer 2

By definition, we have to:

$vf = a * t + vo$

Where,

vf: final speed

vo: initial speed

t: time

a: acceleration

Clearing the acceleration we have:

$a = \frac{vf-vo}{t}$

When replacing values we have to take into account two things:

1) Assume that the given speeds are positive

2) The time must be in seconds

The time in seconds is:

$t = 33 * 60\\t = 1980$

Then, replacing values we have:

$a =\frac{7.1-2.7}{1980}$

$a = 0.002 \frac{m}{s ^ 2}$

Answer:

The average acceleration of the treadmill during this period is:

$a = 0.002 \frac{m}{s ^ 2}$