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bagirrra123 [75]
4 years ago
5

When a sound source is moving toward the observer, the observer will hear a higher pitch. This is due to

Physics
2 answers:
Mamont248 [21]4 years ago
5 0
The doppler effect i think. 
torisob [31]4 years ago
5 0

Answer:

Doppler effect

Explanation:

Doppler effect is the effect produced by a moving sound source in which there is a higher pitch for observers towards whom the source is approaching and lower pitch for observers from whom the source is receding.

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a pebble is dropped down a well and hits the water 1.5 seconds later. using the equations for motion with constant acceleration,
Effectus [21]
Let h = the distance from the edge of the wall to the water surface (m).

Use g = 9.8 m/s² and neglect air resistance.

The initial vertical velocity of the pebble is zero.
Because the pebble hits the surface of the water after 1.5 s, therefore
h = (1/2)*(9.8 m/s²)*(1.5 s)² = 11.025 m

Answer:  11.025 m
7 0
4 years ago
Read 2 more answers
A block of mass m = 2.5 kg is attached to a spring with spring constant k = 730 N/m. It is initially at rest on an inclined plan
Alona [7]

Answer:

A) Em = 4.41 J

B) L = 0.33m

Explanation:

A) The total mechanical energy of the block is the elastic potential energy due to the compressed spring. The gravitational energy is zero. Then you have:

E_m=\frac{1}{2}k(\Delta x)^2

k: constant's spring = 730 N/m

Δx: distance of the compression = 0.11m

You replace the values of k and Δx:

E_m=\frac{1}{2}(730N/m)(0.11m)^2=4.41\ J

B) To find the distance L traveled by the block you take into account that the total mechanical energy of the block is countered by the work done by the friction force, and also by the work done by the gravitational energy.

Then, you have:

E_m-W_f-W_g=0\\\\W_f=(\mu Mg cos\theta)L\\\\W_g=(Mgsin\theta)L

μ:  coefficient of kinetic friction = 0.19

g: gravitational acceleration = 9.8m/s^2

M: mass of the block = 2.5kg

θ: angle of the inclined plane = 21°

You replace the values of all parameters:

E_m-W_f-W_g=0\\\\4.41-(0.19)(2.5kg)(9.8m/s^2)(cos21\°)L-(2.5kg)(9.8m/s^2)(sin21\°)L=0\\\\4.41-4.34L-8.78L=0\\\\4.41-13.12L=0\\\\L=0.33m

hence, the distance L in which the block stops is 0.33m

5 0
3 years ago
The car was initally traveling at 25 m/s. The car slows with a negative acceleration as shown. How long does it take the car to
Karolina [17]

Answer:

<h2>t = 2.35s</h2>

Explanation:

Using one of the equation of motion expressed as v = u+at where;

v is the final velocity = 2.0m/s

u is the initial velocity = 25m/s

a is the acceleration = -a (since the acceleration is negative)

t is the time taken

Substituting the given parameters into the formula above;

2.0 = 25-9.81t

subtract 25 from both sides

2.0 - 25 = 25-9.81t - 25

-23 = -9.81t

Divide both sides by -9.81

-23/-9.81 = -9.81t/-9.81

t = 23.0/9.81

t = 2.35s

<em>Hence it took the car 2.35s to slow to a final velocity of 2.0 m/s</em>

4 0
3 years ago
Dara ran on a treadmill that had a readout indicating the time remaining in her exercise session. When the readout indicated 24
Anastasy [175]

Answer:

97 minutes and 12 seconds

Explanation:

Let x be the total time

From the first statement

\frac{10}{100}x=24\times 60+18\\\Rightarrow 0.1x=1458\\\Rightarrow x=\frac{1458}{0.1}\\\Rightarrow x=14580\ seconds

Total time of Dara's exercise is 14580 seconds

40 %

\frac{40}{100}\times 14580=5832\ seconds

\frac{5830}{60}=97.2\ minutes=97+0.2\times 60\\ =97\ minutes\ and\ 12\ seconds=1\ hour\ 37\ minutes\ and\ 12\ seconds

Time when she had completed 40% was 1 hour 37 minutes and 12 seconds

5 0
3 years ago
Like the polar bear, the walrus is a strong swimmer, although it does not have the same endurance. For short periods of time, a
mr_godi [17]
The answer should be 35.89 meters in 3.4 minutes. I dont know for sure though
4 0
3 years ago
Read 2 more answers
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