Answer:
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first of all there is only two types of selective breeding and they are hybridization and inbreeding.
For plato users
the answer is a. O2(l) O2(g)
hope this helps!
Given mass of Scandium = 50.0 g
Increase in temperature of the metal when heated = 
Heat absorbed by Scandium = 
The equation showing the relationship between heat, mass, specific heat and temperature change:

Where Q is heat = 
m is mass = 50.0 g
ΔT = 
On plugging in the values and solving for C(specific heat) we get,
=50.0g(C)(
)
C = 0.491
Specific heat of the metal = 0.491