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valentina_108 [34]
3 years ago
5

la edades de tres jovenes estan en progresion aritmetica creciente cuya suma es 39 si la suma de sus cuadrados es 515 la edad de

menores ​
Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0
Muy bueno senor idk how to answer this bc I don’t speak Mexican
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Tell me a joke, who ever's joke I like better will get a Brainlist
FromTheMoon [43]

I wanted to be king because I saw dream of king

one day when I visit to dentist

Dentist: "You need a crown." -

Patient: "Finally someone who understands me"

6 0
2 years ago
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A total of 430 tickets were sold for the school play . They were either adult tickets or student tickets . There were 70 fewer s
Maurinko [17]
So first we assume that half is adult and have is student.

So
215 adult  215 student

Now since it said they were 70 less student tickets than adult tickets we subtract 70.
215 - 70 = 145

Now we add the 70 we subtracted from student tickets to the adult tickets.
215 + 70 = 285

So there were 
285 adult tickets sold and 145 student tickets sold

I hope this helped. Have a great day!
6 0
2 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
Help I will give brainless
Reptile [31]

Answer:

1) -4       2)-3        3) -2     4) -1    5) 0

Step-by-step explanation:

4 0
2 years ago
2.5 hours travelled and 187 distance traveled in miles ( I have to find the unit rate)
Elena L [17]

Answer:

The first one is 75 and the second one is 81

Step-by-step explanation:

put 187.5 into calculator then divide it by the bottom number/denominator in this case 2.5 and then you get 75

put 303.75 into calculator then divide it by the denominator or 3.75 and you get an answer of 81

so 81 miles per hour

I really hope this helps!

8 0
3 years ago
Read 2 more answers
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