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rosijanka [135]
3 years ago
14

Which list of elements is arranged in order of increasing electronegativity?

Chemistry
2 answers:
muminat3 years ago
6 0
K, ca, sc is the right answer. Take a look at table S of your chemistry reference table. 
alina1380 [7]3 years ago
4 0

Answer: Option (c) is the correct answer.

Explanation:

Electronegativity is defined as the ability of an atom or element to attract the electrons from another atom towards itself.

Non-metals are the species which are electronegative in nature. Whereas metals are the species which are electropositive in nature.

For example, F, l, Br and I are group 17 elements. These are electronegative in nature but their electronegativity decreases from fluorine to I.

Whereas Li, Na, K are alkali metals and most electropositive in nature.

Similarly, Be, Mg, Ca are group 2 elements and they are also electropositive in nature. When we move from top to bottom in a group then there is a decrease in electronegativity of the non-elements.

But when we move from left to right in a period then due to decrease in size of the atoms there will be increase in electronegativity of the atoms.

Thus, we can conclude that K, Ca, Sc list of elements is arranged in order of increasing electronegativity.

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A ridged steel tank filled with 62.7L of nitrogen gas of 85.0L atm
mylen [45]

The final gas pressure : 175.53 atm

<h3>Further explanation</h3>

Maybe the complete question is like this :

A ridged steel tank filled with 62.7 l of nitrogen gas at 85.0 atm and 19 °C is heated to 330 °C while the volume remains constant. what is the final gas pressure?

The volume remains constant⇒Gay Lussac's Law  

<em>When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature  </em>

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

P₁=85 atm

T₁=19+273=292 K

T₂=330+273=603 K

\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{85\times 603}{292}\\\\P_2=175.53~atm

8 0
3 years ago
A particular flask has a mass of 17.4916 g when empty. When filled with ordinary water at 20.0°c (density = 0.9982 g/ml), the ma
LUCKY_DIMON [66]

The mass of the empty flask is 17.4916 g. Now after feeling the ordinary water the mass of the flask is 43.9616 g. Thus the change of weight due to addition of ordinary water is (43.9616 - 17.4916) = 26.47 g.

Now as the density of the ordinary water at 20°C is 0.9982 g/ml, so 26.47 g is equivalent to \frac{26.47}{0.9982}=26.5177 mL of water. Thus the capacity of the flask is 26.5177 mL.

Now the density of heavy water is 1.1053 g/mL at 20°C. Thus 26.5177 mL of heavy water is equivalent to (1.1053×26.5177) = 29.310 g.

Thus the total weight of the flask filled with heavy water will be (17.4916 + 29.310) = 46.8016 g at 20°C.  

4 0
3 years ago
Read 2 more answers
A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co
KengaRu [80]
In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

Given 
P = 10130.0 kPa 
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Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT                      PV
----    ------    --->    n = --------
 RT     RT                       RT

          10130.0 kPa  x 50 L
n= ---------------------------------------------
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  =  ----------------------------
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=106.29 mol Ar

So the moles of argon gas is 106.29 moles 
8 0
3 years ago
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laila [671]

Answer:false

Explanation:

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3 years ago
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AnnyKZ [126]

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(Question 2 points 3).

This is because they are lightweight, spread easily, less volatile and are relatively persistent in the environment.

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