Question

What is the [OH-] in a solution with a poh of 3.90

Answer 1

Answer:

7.9433E-3

Explanation:

POH=-log OH

3.90=POH

OH=ANTILOG OF -3.90

=7.9433×10^-3

Answer 2

Answer: The hydroxide ion concentration is $1.26\times 10^{-4}M$

Explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration in the solution.

To calculate the pOH of the reaction, we use the equation:

$pOH=-\log[OH^-]$

where,

$pOH=3.90$

Putting values in above equation, we get:

$3.90=-\log[OH^-]$

$[OH^-]=1.26\times 10^{-4}M$

Hence, the hydroxide ion concentration is $1.26\times 10^{-4}M$