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Ulleksa [173]
3 years ago
5

A parabola and a circle are graphed into the standard (x,y) coordinate plane. The circle has a radius of 4 and is centered at (1

,1). The parabola, which has a vertical axis of symmetry, has its vertex at (1,5) and a point at (2,4). How many points of intersection exist between the parabola and the circle?
Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

Correct answer: Two point of intersection and one touch point.

Step-by-step explanation:

Cartesian form of parabola is: y= a(x-1)² + 5  and point named A(2,4)

when we replace the coordinates of the point A in the formula we get

a = - 1 and parabola is  y= - (x-1)² + 5 which means that it faces the opening downwards. The parabola touches the circle in vertex.

God is with you!!!

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Given that normally distributed data set has a mean of 55 and 99.7% of data fall between 47.5 and 62.5.

Let s be the standard deviation of data set.

Since 99.7% data fall within 3 standard deviations of mean, z-value for 47.5 and 62.5 has an absolute value of 3.

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That is |\frac{47.5-55}{s}|  = 3

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Brainliest + Points!<br><br> Please show your work so I can understand this problem!
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Answer:

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Step-by-step explanation:


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Step-by-step explanation:

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