Answer:
Explanation:
The resultant velocity of the motorboat due to the current perpendicular to the motion of the boat can be calculated by drawing a triangle to represent this motion. The velocity of the motorboat is the base whereas the velocity of the river is the perpendicular of the triangle (picture attached).
The angle is (perpendicular/base);
(5/20)= 14.0;
The triangle can be enlarged such that the perpendicular now represents the width of the river and the perpendicular represents the distance between the dock and landing place.
The distance between dock and landing place is:
a) base*Tan(∅) = 2*Tan(14) = 0.5km
b Time = 2/20= 0.1 hours. This is because the horizontal component of the motion due to velocity of motor boat will be considered for horizontal distance of 2 km.
Answer:
the constant force applied by Kitty is 8 N.
Explanation:
Given;
work done by Kitty, W = 32 J
distance moved by Kitty's trolley, d = 4 m
Let the constant force applied by Kitty = F
The work done by Kitty is calculated as follows;
W = F x d
F = W / d
F = 32 / 4
F = 8 N.
Therefore, the constant force applied by Kitty is 8 N.
Answer:
Mechanical advantage = 3
Explanation:
Given:
Weight = 300 N
Force load = 100 N
Find:
Mechanical advantage:
Computation:
Mechanical advantage = Weight/Force Load
Mechanical advantage = 300/100
Mechanical advantage = 3
Answer:
the wave length becomes doubled or becomes two times the initial wavelength = 240 cm
Explanation:
From wave,
v = λf................ Equation 1
Where v = velocity of the wave, λ = wavelength of the wave, f = frequency of the wave.
Given: f = 1200 Hz, λ = 120 cm = 1.2 m
Substitute into equation 1
v = 1200(1.2)
v = 1440 m/s.
When the ship sent out a 600 Hz sound wave,
make λ the subject of formula in equation 1
λ = v/f............. Equation 2
Given: f = 600 Hz, v = 1440 m/s
Substitute into equation 2
λ = 1440/600
λ = 2.4 m or 240 cm.
When the ship sent out a 600 Hz sound wave instead, the wave length becomes doubled or becomes two times the initial wavelength = 240 cm
Answer:
112 m/s², 79.1°
Explanation:
In the x direction, given:
x₀ = 0 m
x = 19,500 cos 32.0° m
v₀ = 1810 cos 20.0° m/s
t = 9.20 s
Find: a
x = x₀ + v₀ t + ½ at²
19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²
a = 21.01 m/s²
In the y direction, given:
y₀ = 0 m
y = 19,500 sin 32.0° m
v₀ = 1810 sin 20.0° m/s
t = 9.20 s
Find: a
y = y₀ + v₀ t + ½ at²
19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²
a = 109.6 m/s²
The magnitude of the acceleration is:
a² = ax² + ay²
a² = (21.01)² + (109.6)²
a = 112 m/s²
And the direction is:
θ = atan(ay / ax)
θ = atan(109.6 / 21.01)
θ = 79.1°