Answer:
Explanation:
The magnetic force due to lower rod must be equal to weight of upper rod for equilibrium .
magnetic field due to lower rod on upper rod
= ( μ₀ / 4π ) x(2i / r ) , i is current , r is distance between rod
= 10⁻⁷ x 2 x 15 / 1.5 x 10⁻³
= 20 x 10⁻⁴ T
force on the upper rod
= B i L , B is magnetic field , i is current in second rod and L is its length
= 20 x 10⁻⁴ x 15 x .50
= 150 x 10⁻⁴ N
= .015 N
This force can balance a wire having weight equal to .015 N .
= .00153 kg
= 1.53 g .
wire should weigh 1.53 g .
Answer:
B. 4a
Explanation:
Force between the charges is inversely proportional to the square of the distance
=> Force will be 4 times and acceleration will be 4a
=> Answer b).
For this problem, we use the equations derived for rectilinear motion at constant acceleration. The equations are:
a = (v - v₀)/t
x = v₀t + 0.5at²
where
a is acceleration
v and v₀ are the final and initial velocities, respectively
x is the distance
t is the time
First, let's determine the a to be used in the second equation:
a = (7.5 m/s - 0 m/s)/1.7 s = 4.411 m/s²
x = (0)(1.7s) + 0.5(4.411 m/s²)(1.7 s)²
x = 6.375 m