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Fed [463]
3 years ago
7

What is the best explanation for the observation that the electric charge on the stem became positive as the charged bee approac

hed (before it landed?

Physics
1 answer:
topjm [15]3 years ago
3 0

Answer:

Option B seems to be the appropriate choice,

Explanation:

The given question is incomplete. Please find the attachment of the complete question.

  • From either the principle or law of the Coulombs, there would have been either pressure (force) through attachment or repulsion amongst charges.  
  • It is evident from the analysis presented that perhaps the bee becomes positively (+) charged and would have been drawn either by negatively (-) charged roots of the plants or stem.    

As a consequence, the vegetation is electric current polarized because as activated bee pursued.

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A hydrogen atom contains a single electron that moves in a circular orbit about a single proton. Assume the proton is stationary
riadik2000 [5.3K]

Answer:

Radius between electron and proton= 6.804\times 10^{-10}m

Explanation:

The motion of the electron is carried out in the orbit due to the balancing of the electrostatic force between the proton and the electron and the centripetal force acting on the electron.

The electrostatic force is given as = \frac{kq_1q_2}{r^2}

Where,

k = coulomb's law constant (9×10⁹ N-m²/C²)

q₁ and q₂  = charges = 1.6 × 10⁻¹⁹ C

r = radius between the proton and the electron

Also,

Centripetal force on the moving electron is given as:

=\frac{m_eV^2}{r}

where,

m_e = mass of the electron (9.1 ×10⁻³¹ kg)

V = velocity of the moving electron (given: 6.1 ×10⁵ m/s)

Now equating both the formulas, we have

\frac{kq_1q_2}{r^2} = \frac{m_eV^2}{r}

⇒r = \frac{kq_1q_2}{m_eV^2}

substituting the values in the above equation we get,

r = \frac{9\times 10^{9}\times (1.6\times 10^{-19})^2}{9.1\times 10^{-31}\times (6.1\times 10^5)^2}

⇒r = 6.804\times 10^{-10}m

3 0
3 years ago
A crate with a mass of 175.5 kg is suspended from the end of a uniform boom with a mass of 94.7 kg. The upper end of the boom is
kotykmax [81]

323.5 N is the tension in the cable.

Given

Mass of crate(M) = 175.5 kg

Mass of boom(m) = 94.7 kg

The tension, T in the cable can be calculated by taking moments of force about the central point of marked X.

The Angle of the boom with the horizontal can be calculated by

tanθ = 5/10

θ = tan⁻¹(5/10) = 26.56°

Angle of the boom with horizontal is 26.56°

The angle of cable with horizontal can be calculated by

tan B = 4/10

B = tan⁻¹(4/10) = 21.80°

Angle of cable with horizontal is 21.80°

Taking moments of force about the point X

(Mcosθ + mcosθ) 0.5 = T(sin(θ +B)1

(175.5 × cos 26.56 + 94.7 × cos 26.56 )× 0.5 = T (sin(26.56 + 21.80) X 1

By calculating, we get

Tension(T) = 241.68/0.747

Tension(T) = 323.5 N

Hence, 323.5 N is the tension in the cable.

Learn more about Tension here brainly.com/question/24994188

#SPJ1

8 0
2 years ago
It's important to maintain muscle flexibility by stretching only after aerobic exercise.
lions [1.4K]

Answer: Most aerobic and strength training programs cause your muscles to contract and tighten. So stretching after you exercise helps optimize the range of motion about your joints and boosts circulation.

Hope this helps!

4 0
3 years ago
What is one possible effect of a hurricane in Florida?
Mice21 [21]

Answer:

The answer is B.

Explanation:

Hurricanes are known to cause strong storms and heavy flooding.

6 0
3 years ago
Read 2 more answers
I need some help with my science homework about energy, work, and power. It would be greatly appreciated :)
fgiga [73]

Answer:

1. B

Explanation:

Work = Force × Distance

Work = 4N × 1.5M

5 0
4 years ago
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