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Fed [463]
3 years ago
7

What is the best explanation for the observation that the electric charge on the stem became positive as the charged bee approac

hed (before it landed?

Physics
1 answer:
topjm [15]3 years ago
3 0

Answer:

Option B seems to be the appropriate choice,

Explanation:

The given question is incomplete. Please find the attachment of the complete question.

  • From either the principle or law of the Coulombs, there would have been either pressure (force) through attachment or repulsion amongst charges.  
  • It is evident from the analysis presented that perhaps the bee becomes positively (+) charged and would have been drawn either by negatively (-) charged roots of the plants or stem.    

As a consequence, the vegetation is electric current polarized because as activated bee pursued.

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Answer:

The answer is 1.0 N

Explanation:

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Now this gravitational force has two component i.e.

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A car speedometer has a 6% uncertainty. What is the range of possible speeds when it reads 100 km/h?
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Make the following conversion. 0.0097 mg = _____ g
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4 years ago
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What is the weight of a feather (mass = 0.0001 kg) that floats through earth's and the moon's atmospheres?
olya-2409 [2.1K]

Weight = (mass) x (acceleration of gravity)

Acceleration of gravity = 9.81 m/s² on Earth, 1.62 m/s² on the Moon.

The feather's weight is . . .

On Earth:  (0.0001 kg) x (9.81 m/s²) = <em>0.000981 Newton </em>

On the Moon:  (0.0001 kg) x (1.62 m/s²) = <em>0.000162 N</em>

The presence or absence of atmosphere makes no difference.  In fact, the numbers would be the same if the feather were sealed in a jar, or spinning wildly in a tornado, or hanging by a thread, or floating in a bowl of water or chicken soup.  Weight is just the force of gravity between the feather and the Earth.  It's not affected by what's around the feather, or what's happening to it.

6 0
3 years ago
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To solve this problem, we must remember about the law of conservation of momentum. The initial momentum mist be equal to the final momentum, that is:

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Since we are not given the masses of each car m1 and m2, so let us assume that they are equal, such that:

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50 + 48 = 2 v’

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v ‘ = 49 km/h

 

<span>The speed of impact is 49 km/h.</span>

6 0
3 years ago
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