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hoa [83]
3 years ago
10

Please help do not guess

Physics
1 answer:
Georgia [21]3 years ago
8 0

Answer:

358.9 (+/- 0.4) million years ago

Holocene Epoch, of the Quaternary Period

Devonian period

66 million years ago (prox)

521 million years ago

110,000 years ago

NW

North america became more cold when it moved NW

Explanation:

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Which of the following is an example of an immiscible liquid?
Nonamiya [84]

Answer:

the answer is 1, oil and water

4 0
3 years ago
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At high speeds, a particular automobile is capable of an acceleration of about 0.540 m/s^2. At this rate, how long (in seconds)
Mama L [17]

Answer:

t = 6.68 seconds

Explanation:

The acceleration of the automobile, a=0.54\ m/s^2

Initial speed of the automobile, u = 91 km/hr = 25.27 m/s

Final speed of the automobile, v = 104 km/hr = 28.88 m/s

Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :

t=\dfrac{v-u}{a}

t=\dfrac{28.88-25.27}{0.54}

t = 6.68 seconds

So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.

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3 years ago
Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground
Setler79 [48]
They will both hit the ground at the same time because gravitational acceleration for all objects is the same.
6 0
3 years ago
The fact that some well-known studies have been repeated without finding results consistent with those in the initial report des
ValentinkaMS [17]

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Replication Crisis

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6 0
2 years ago
A velocity selector in a mass spectrometer uses a 0.150 T magnetic field. (a) What electric field strength (in volts per meter)
Alekssandra [29.7K]

Answer:

The electric field strength is 6.6\times10^{5}\ V/m

Explanation:

Given that,

Magnetic field = 0.150 T

Speed v= 4.40\times10^{6}\ m/s

We need to calculate the electric field strength

Using formula of velocity

v=\dfrac{E}{B}

E=v\times B

Where, v = speed

B = magnetic field

Put the value into the formula

E=4.40\times10^{6}\times0.150

E=660000\ V/m

E=6.6\times10^{5}\ V/m

Hence, The electric field strength is 6.6\times10^{5}\ V/m

4 0
3 years ago
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