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jenyasd209 [6]
3 years ago
7

What happened to the combined energy of the two sleds when they collided?

Physics
1 answer:
Komok [63]3 years ago
8 0
Hi!
Here’s your answer:

What happened to the combined energy of the two sleds when they collided? It changed forms into another energy C. Because energy is conserved, the “lost” energy has actually been changed into other forms.

Hope this helps have a good day!!<3
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The free-body diagrams of four objects are shown.
kipiarov [429]

Answer:

its unbalanced and balanced

Explanation:

5 0
3 years ago
A treasure map instructs you to walk (25.0+A) m south, followed by (18.0+B) m east, then 64.5 m north, and finally 28.5 m east.
adelina 88 [10]

Answer:

Explanation:

Check attachment for solutions

3 0
3 years ago
A passenger is running inside a stationary train with some speed and looks at the person standing on the platform. Describe the
Lubov Fominskaja [6]

Answer:

Doppler effect

Explanation:

this means that at one point when the person running is close to the observer it will appear to run fast but slower as he moves away from the observer

4 0
2 years ago
When Royce was 10 years old, he had a mass of
coldgirl [10]

Answer:

<em>The gravitational force between Royce and Earth would be doubled at 16 years.</em>

Explanation:

<em>"Newton's law of universal gravitation states that gravitation force between two masses is proportional to the magnitude of their masses and inverse-squared of their distance".</em>

Royce Scenario

At the age of 10 Royce's mass = 30kg

At the age of 16 Royce's mass = 60kg

From Newton's law of universal gravitation, an Increase in the mass of a body would amount to a corresponding increase in the gravitational force.

In the case of Royce, the mass double between the age of 10 and 16, so there would be an increase of the gravitation force by double.

6 0
3 years ago
A wire 6.90 m long with diameter of 2.15 mm has a resistance of 0.0320 Ω. Find the resistivity of the material of the wire. rho
spayn [35]
<h2>Answer:</h2>

1.68 x 10⁻⁸Ωm

<h2>Explanation:</h2>

The resistance (R) of a wire is related to its length(L), its material resistivity(ρ) and its crossectional area(A) as follows;

R = ρL/A               ------------------------(i)

Where;

A = πd² / 4              [where d = diameter of the wire]

From the question;

L = 6.90m

d = 2.15mm = 0.00215m

R = 0.0320Ω

First calculate the crossectional area (A) of the wire as follows;

A = πd² / 4      

[Take π = 3.142]

d = 0.00215m

∴ A = 3.142 x (0.00215)² / 4

∴ A = 0.000003631m²

Now, substitute the values of A, L, and R into equation (i) as follows;

R = ρL/A

0.0320 = ρ x 6.90 / 0.000003631

0.0320 = 1900302.95 x ρ

Solve for ρ;

=> ρ = 0.0320 / 1900302.95

=> ρ = 1.68 x 10⁻⁸Ωm

Therefore, the resistivity of the material of the wire is 1.68 x 10⁻⁸Ωm

4 0
3 years ago
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