Answer:
The only incorrect statement is from student B
Explanation:
The planet mercury has a period of revolution of 58.7 Earth days and a rotation period around the sun of 87 days 23 ha, approximately 88 Earth days.
Let's examine student claims using these rotation periods
Student A. The time for 4 turns around the sun is
t = 4 88
t = 352 / 58.7 Earth days
In this time I make as many rotations on itself each one with a time to = 58.7 Earth days
#_rotaciones = t / to
#_rotations = 352 / 58.7
#_rotations = 6
therefore this statement is TRUE
student B. the planet rotates 6 times around the Sun
t = 6 88
t = 528 s
The number of rotations on itself is
#_rotaciones = t / to
#_rotations = 528 / 58.7
#_rotations = 9
False, turn 9 times
Student C. 8 turns around the sun
t = 8 88
t = 704 days
the number of turns on itself is
#_rotaciones = t / to
#_rotations = 704 / 58.7
#_rotations = 12
True
The only incorrect statement is from student B
Answer:
You were a freeloader of my questions, so I'll be one too.
Angular frequency in radian per second for 20 vibrations in 10 seconds is 12.6 rad/s
<h3>What is Angular frequency?</h3>
Angular frequency is the number of vibrations in radian per second.
The total number of vibrations n is 20 and the time taken for these vibrations is 10 s
The frequency of the vibrations will be
f = 20 / 10 = 2 Hz
Angular frequency is related to the frequency as
ω = 2πf
ω=2π × 2
ω = 12.6 rad/s
Thus, the angular frequency is 12.6 rad/s.
Learn more about Angular frequency.
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Kinetic energy = 1/2 * m * V^2
K = 1/2 * 2kg * 4
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