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lesya692 [45]
3 years ago
14

What is the difference between kinetic energy and potential energy​

Physics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer:

Kinetic energy is the energy of a moving body while potential energy is the energy by vutue of it's position

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How did J.J. Thomson's experiments demonstrate that Dalton's model of the atom was incorrect?
morpeh [17]
The correct option is C.
J.J Thompson demonstrated that Dalton's model of the atomic theory was wrong by showing that atoms are made up of sub particles, this is contrary to the report that Dalton gave about atoms. In his experiment, Dalton reported that atoms are indivisible, that is, they can not be broken down into smaller particles. J.J Thompson on the other was able to show through his cathode ray experiment that atoms are made up of smaller particles called electrons.

4 0
2 years ago
Read 2 more answers
James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.
belka [17]

a. The most momentum is attained by James.

b. The resultant force acting on her is 90.77N.

c. Time taken for him to stop is  3.24 s

<h3>What is momentum?</h3>

Momentum of any object is the product of the velocity of the object and its mass.

P =mv

James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.

a.

Substitute the values, we get

P jane= 98 kg x 3

P jane= 294 kg.m/s

Momentum of Basma, is

P Basma = 59 kg x 4

P Basma = 236  kg.m/s

Therefore, the momentum is large for James.

b. Basma approaches a road, so she stops quickly. It takes her 2.6 seconds to stop. The resultant force acting on her

F. t = P Basma

F =[ 236/2.6

F = 90.77 N

Thus, the resultant force on Basma is 90.77 N.

c. James also stops for the road. If he were to have the same resultant force acting on him, Time taken for him to stop is

F = 90.77 = P james/t

t = 294 / 90.77

t = 3.24 s

Thus, time taken for James to stop for the same resultant force is  3.24 s

Learn more about momentum.

brainly.com/question/4956182

#SPJ1

5 0
1 year ago
When the pivot point of a balance is not at the center of mass of the balance, how is the net torque on the balance calculated
Mashcka [7]

Answer:

It is calculated as Force × perpendicular distance.

Explanation:

Torque is a rotational force and twisting force that can cause an object to rotate in it's axis. This cause angular rotation.

The torque due to gravity on a body about its centre of mass is zero because the centre of mass is the that point of the body at which the force acts by the gravity that is mg.

But if the pivot point of a balance is not at the centre of mass of the balance, it will be FORCE × PERPENDICULAR DISTANCE because at that point, there is no centre in which the force act on a body by gravity. The distance and force will be use to calculate.

6 0
3 years ago
A mountain 10.0 km from a person exerts a gravitational force on him equal to 2.00% of his weight. (a) Calculate the mass of the
LiRa [457]

Answer:

a)   M = 2,939  10¹⁷ kg , b)   M_{e} / M  = 2 10⁷

Explanation:

a) The equation for gravitational force is

         F = G m M / r²

Where G is the gravitational constant that is worth 6.67 10⁻¹¹ N m² / kg², m the mass epa person. M the mass of the Mountain and r the distance between them.

The value of this force is 2% of the person's weight

          F = 0.02 W = 0.02 mg

we replace

         0.02 mg = G m M / r²

         M = 0.02 g r² / G

         r = 10 km = 10 10³ m = 1.0 10⁴ m

         M = 0.02  9.8  (10⁴)² / 6.67 10⁻¹¹

         M = 2,939  10¹⁷ kg

b) to compare the masses we find their relationship

       M_{e} / M = 5.98 1024 / 2,939 1017

       M_{e} / M  = 2 10⁷

c) treating the mountain as a point object

d) The mountain is not spherical so the distance changes depending on the height of the mountain

8 0
3 years ago
The position versus time for a certain object
Alex787 [66]
To find instantaneous velocity given a position vs. time graph is find the derivative at that given point. In other words, find the slope at that point.

So at t = 1s, the velocity is 5/2 m/s.

Hope this helps!
5 0
2 years ago
Read 2 more answers
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