Answer:
A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same
B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same
Explanation:
A vehicle crash problem must be solved with the equation of the moment,
Initial instant Before crash
p₀ = m v₁ + mv₂
After the crash
= m
+ m 
p₀ = 
If the speed ratio before and after the crash is one
p₀ /
= 1
We can assume that initially one of the cars was stopped
m v₁₀ = m 
v₁₀ = 
For the two speeds to be equal, the masses of the vehicles must be the same.
A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same
B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same
Answer:
The speed of the sled is 9.2 m/s
The speed of the boulder is 0.82 m/s
Solution:
As per the question:
Mass of the boulder,
Mass of the sled,
Mass of the boy,
Initial Velocity, v = 10.0 m/s
Now,
To calculate the speed of both the sled and the boulder after the occurrence of the collision:
m = 
Initial velocity of the boulder, 
Since, the collision is elastic, both the energy and momentum rem,ain conserved.
Now,
Using the conservation of momentum:

where
v' = final velocity of the the system of boy and sled
= final velocity of the boulder

(1)
Now,
Using conservation of energy:


(2)
Now, from eqn (1) and (2):


Now,


Answer:
Explanation:
Given
Wall is
in area
requires 1 gallon of paint
so using unitary method
gallon of paint
wall will require
gallons of paint

TheThe distance they have covered for trip is 219Km.
<h3>What do you mean by uniformly accelereted motion?</h3>
When an object is traveling in a straight line with an increase in velocity at equal intervals of time.
The total time for the trip is
T→ t1+ 22 min = t1+ 0.367 h ,where t1 is the time spent traveling at
V1= 89.5 km/ h .
the distance traveled is ∆x = V1t1=Vavg T
after applying value and calculating it we get
t1= 2.44h for a total time of
t total we get 2.81 h .
∆x =V1T1 = VavgTtotal
∆x = 77×2.81= 219 Km
to learn more about Uniform accelereted motion click here brainly.com/question/12920060
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