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4 years ago

The bond between which two atoms is most polar?

Chemistry

2 answers:

blondinia [14]4 years ago

8 0

Answer:

The correct answer is (4) I and F

Explanation:

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas. The shared electron pair is common to the two atoms and holds them together.

The covalent bond between two atoms can be polar or nonpolar. If the molecule composed of two atoms of the same element is considered, a pair of electrons is shared that is attracted with the same intensity by the two nucleos. So the bond is non polar. However, when different atoms are linked, this bond will not always be performed symmetrically. Then this bond will be polar, and depends on the difference in electronegativity of the elements that bind (Electronegativity is called the tendency that the atom of a given element presents to attract electrons). The greater the electronegativity difference, the greater the polar character the bond has. The most electronegative element will be the one that attracts the shared electrons with more force, then a negative partial charge will be generated on said element, while in the other element (less electronegative) a positive partial charge will be generated.

First, to determine the link with greater polarity it is convenient to know the electronegativity of each element:

Br: 2.8
Cl: 3.0
F: 4.0
I: 2.5

Knowing the electronegativity of each element, it is possible to determine the electronegativity difference of each bond:

Br and Cl: 3.0-2.8=0.2
Br and F: 4.0-2.8=1.2
I and Cl: 3.0-2.5=0.5
I and F: 4.0-2.5=1.5

The bond between iodine I and fluorine F have the greatest electronegativity difference, indicating that this bond is the one with the highest polarity.

As the fluorine has greater electronegativity, the shared electrons are attracted more strongly by this element and a negative partial charge is generated on the fluorine. And in the iodine a positive partial charge is generated.

So, <em><u>the correct answer is (4) I and F</u></em>

zalisa [80]4 years ago

3 0

The answer to your question is 4. I and F.

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NemiM [27]

KE = (1/2)mv^2
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3 years ago

the pressure inside each of two identical cylinders is equal to atmospheric pressure. one cylinder contains hydrogen, the other

ycow [4]

The number of moles of hydrogen is equal to the number of moles of nitrogen.

According to the ideal gas equation

PV = nRT

where

P = the pressure of the gas
V = the volume of gas
n = the total amount of ideal gas (moles)
R = the universal gas constant
T = the temperature

In the problems there are two identical cylinders means, V₁ = V₂

The pressure inside each of two identical cylinders is equal to atmospheric pressure means, P₁ = P₂

Both gases are at the same temperature, means T₁ = T₂

$\frac{P_1 V_1}{P_2 V_2} \:=\: \frac{n_1 RT_1}{n_2 RT_2}$

$\frac{P_1 V_1}{P_2 V_2} \:=\: \frac{n_1 T_1}{n_2 T_2}$

n₁ = n₂

So the total amount of hydrogen gas is equal to total amount of ideal nitrogen gas.

Learn more about the ideal gas equation here: brainly.com/question/27870704

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1 year ago

Convert 7.89 x 10^8 molecules of water to liters.

NNADVOKAT [17]

Answer:

2.94 x 10⁻¹⁴L

Explanation:

To solve this problem, we have to assume that the condition of this water is at standard temperature and pressure, STP.

At STP;

1 mole of gas have a volume of 22.4L

So, let us find the number of moles of this water first;

6.02 x 10²³ molecules can be found in 1 mole of a substance

7.89 x 10⁸ molecules will contain $\frac{7.89 x 10^{8} }{6.02 x 10^{23} }$ = 1.31 x 10⁻¹⁵mole of water

So;

Volume of water = 22.4 x 1.31 x 10⁻¹⁵ = 2.94 x 10⁻¹⁴L

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3 years ago

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Inessa [10]

Answer:

Explanation:

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3 years ago

Read 2 more answers

How many grams of carbon dioxide will form if 5.5 g of C3H8 burns in 15 g of O2?

mr Goodwill [35]

C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
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4 years ago