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Thepotemich [5.8K]
3 years ago
14

Do 4x and 15 + x have the same value when x is 5? How do you know?

Mathematics
2 answers:
Masteriza [31]3 years ago
6 0
Yes, 4x = 4x5 which is 20. 15 + 5 is also 20 so it is equal
uysha [10]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

4(5)= 20 and

15 + 5 = 20

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Which of the following is the inverse of f(x)=4x-10?
Anastasy [175]
Injective- (one-to-One)
so
Replace the f(x) with y 
10-4x
Interchange the variables
x=10-4y
Solv for y.
y= 5/2 - x/4
So solve for y and replace with f-1 (x).
and it equals 
f-1 (x)=5/2- x/4
5 0
3 years ago
Find the straight time pay $7.60 per hour x 40 hours
gayaneshka [121]

Answer:

The straight time pay for $ 7.60 per hour and 40 work hours per week is $ 304.

Step-by-step explanation:

Let suppose that worker is suppose to work 8 hours per day, so that he must work 5 days weekly. The straight time is the suppose work time in a week, the pay is obtained after multiplying the hourly rate by the amount of hours per week. That is:

C = \left(\$\,7,60/hour\right)\cdot (40\,hours)

C = \$\,304

The straight time pay for $ 7.60 per hour and 40 work hours per week is $ 304.

5 0
3 years ago
Simplify the rational expression <br> x^4 y^2/xy^7.
sammy [17]

Answer: x^3y^9

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): Dot was discarded near "7.".

<u>STEP 1: </u>

Simplify \frac{y^2}{x}

<u>The equation at the end of step 1:</u>

((x^4)*\frac{y^2}{x} )*y^7

<u>Multiplying exponential expressions:</u>

2.1    y^2 multiplied by y^7 =y^(2+7)=y^9

Final result is x^3y^9

8 0
2 years ago
Each day, X arrives at point A between 8:00 and 9:00 a.m., his times of arrival being uniformly distributed. Y arrives independe
astraxan [27]

Answer:

Y will arrive earlier than X one fourth of times.

Step-by-step explanation:

To solve this, we might notice that given that both events are independent of each other, the joint probability density function is the product of X and Y's probability density functions. For an uniformly distributed density function, we have that:

f_X(x) = \frac{1}{L}

Where L stands for the length of the interval over which the variable is distributed.

Now, as  X is distributed over a 1 hour interval, and Y is distributed over a 0.5 hour interval, we have:

f_X(x) = 1\\\\f_Y(y)=2.

Now, the probability of an event is equal to the integral of the density probability function:

\iint_A f_{X,Y} (x,y) dx\, dy

Where A is the in which the event happens, in this case, the region in which Y<X (Y arrives before X)

It's useful to draw a diagram here, I have attached one in which you can see the integration region.

You can see there a box, that represents all possible outcomes for Y and X. There's a diagonal coming from the box's upper right corner, that diagonal represents the cases in which both X and Y arrive at the same time, under that line we have that Y arrives before X, that is our integration region.

Let's set up the integration:

\iint_A f_{X,Y} (x,y) dx\, dy\\\\\iint_A f_{X} (x) \, f_{Y} (y) dx\, dy\\\\2 \iint_A  dx\, dy

We have used here both the independence of the events and the uniformity of distributions, we take the 2 out because it's just a constant and now we just need to integrate. But the function we are integrating is just a 1! So we can take the integral as just the area of the integration region. From the diagram we can see that the region is a triangle of height 0.5 and base 0.5. thus the integral becomes:

2 \iint_A  dx\, dy= 2 \times \frac{0.5 \times 0.5 }{2} \\\\2 \iint_A  dx\, dy= \frac{1}{4}

That means that one in four times Y will arrive earlier than X. This result can also be seen clearly on the diagram, where we can see that the triangle is a fourth of the rectangle.

6 0
3 years ago
12+6<br> What is the value of when N= 2?<br> N<br> O A. 6<br> OB. 9<br> O C. 12<br> O D. 18
Artemon [7]

Answer:

Where is the N in the equation

5 0
3 years ago
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