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kari74 [83]
3 years ago
13

The product of a chemical reaction can never have a greater mass than the reactants true or false

Chemistry
1 answer:
mr_godi [17]3 years ago
4 0

Answer:

True

Explanation:

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Virty [35]

Answer:

Explanation:

So basically it just asking you question about that surtain subject .

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3 years ago
Assuming the compound is dissolved in water, what is the formula for phosphorous acid? h3p h3po4 hp h3po3
IrinaVladis [17]
I think the correct answer from the choices listed above is the last option. The formula for  phosphorous acid is H3PO3. It <span>also called orthophosphorous acid, one of several oxygen acids of phosphorus, used as reducing agent in chemical analysis. Hope this answers the question.</span>
6 0
2 years ago
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Define Atomic mass unit .​
Andrei [34K]

The dalton or unified atomic mass unit is a unit of mass widely used in physics and chemistry. It is defined as 1⁄12 of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state and at rest. The atomic mass constant, denoted mᵤ is defined identically, giving mᵤ = m/12 = 1 Da.

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2 years ago
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a 280.0 mL sample of neon exerts a pressure of 660.0 toff at 26.0 celsius. at what temperture would it exert a pressure of 940.0
bixtya [17]

Answer:

T₂ = 669.2 K

Explanation:

Given data:

Initial pressure = 660 torr

Initial temperature = 26 °C (26 +273 = 299 K)

Final volume = 280 mL ( 280/1000 = 0.28 L)

Final pressure = 940.0 torr

Final volume = 0.44 L

Final temperature = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂ = P₂V₂ T₁ /P₁V₁

T₂ = 940 torr × 0.44 L  × 299 K / 660 torr × 0.28 L

T₂ = 123666. 4 torr. L. K / 184.8 torr. L

T₂ = 669.2 K

3 0
2 years ago
How many grams of NaOH are produced with the reaction of 5.00 moles of water? *
Andre45 [30]

Answer:

200 grams of NaOH are produced with the reaction of 5.00 moles of water

Explanation:

First of all you apply a rule of three to know the amount of moles of NaOH as follows: if 2 moles of water produce 2 moles of NaOH, 5 moles of water how many moles would they produce?

moles of NaOH=\frac{5 moles of water*2 moles of NaOH}{2 moles of water}

moles of NaOH= 5

Being:

  • Na: 23 g/mole
  • O: 16 g/mole
  • H: 1 g/mole

the molar mass of NaOH is: 23 g/mole + 16 g/mole + 1 g/mole= 40 g/mole

Then a rule of three applies as follows: if in 1 mole there are 40 g of NaOH, in 5 moles how much mass is there?

mass=\frac{5 moles*40g}{1  mole}

mass= 200 g

<u><em>200 grams of NaOH are produced with the reaction of 5.00 moles of water</em></u>

4 0
3 years ago
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