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babymother [125]
3 years ago
11

WILL MARK BRAINLY! Which chemical element has the shortest name?

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
5 0

Answer:

boron I guess

hope this heps

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What do two or more atoms form when they share electrons in a chemical bond
dlinn [17]
A covalent bond is your answer
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3 years ago
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Is sugar (C12H22O11) an element or a compound?
Semmy [17]
I believe that sugar is a compound because there are elements that make up sugar
4 0
4 years ago
Draw a bond-line structure for CH3CH2O(CH2)2CH(CH3)2.<br><br> Include Lone Pairs in your answer.
mash [69]

Answer:

See explanation and image attached

Explanation:

A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.

The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.

7 0
3 years ago
What is the percent composition of hydrogen if a sample is found to contain 7 grams of hydrogen, 32 grams of nitrogen, and 7 gra
nata0808 [166]

<u>Answer:</u> The percent composition of hydrogen in the sample is 15.22 %

<u>Explanation:</u>

We are given:

Mass of hydrogen = 7 grams

Mass of nitrogen = 32 grams

Mass of carbon = 7 grams

Total mass of the sample = 7 + 32 + 7 = 46 grams

To calculate the percentage composition of hydrogen in sample, we use the equation:

\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of sample}}\times 100

Mass of sample = 46 g

Mass of hydrogen = 7 g

Putting values in above equation, we get:

\%\text{ composition of hydrogen}=\frac{7g}{46g}\times 100=15.22\%

Hence, the percent composition of hydrogen in the sample is 15.22 %

6 0
3 years ago
(The radioisotope 224Ra decays by alpha emission via two paths to the ground state of its daughter 94% probability of alpha deca
pav-90 [236]

Answer:

a) ²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b) the Q-value of this reaction is 5.789 MeV

c) the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

       

Explanation:

a)

The decay equation for the alpha decay is expressed as;

²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b)

Calculate the Q-value (in MeV) of this reaction.

Q = Mparent - Mdaughter -Mg

Q = MRa - MRn -Mg

= 224.020202 - 220.011384 - 4.00260305

= 0.00621495 amu

= 5.789 MeV

therefore the Q-value of this reaction is 5.789 MeV

c)

Energy of alpha particle is expressed as;

E∝ = MQ / ( m + M)

now this is the maximum energy available for the daughter, ²²⁰Rn going to the ground state;

The energy of the alpha particle gives;

E∝  = 220(5.789) / ( 4 + 220) = 5.69 MeV

as given in the question,The other less frequent alpha occurring 5.5% of the time leaves the daughter nucleus in an excited state of 0.241 MeV above the ground state.

Therefore the energy of this alpha is

E∝ = 5.69 - 0.241 = 5.449 Mev

Therefore the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

d)

Sketch of the nuclear decay scheme have been uploaded along side this answer.

7 0
3 years ago
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