Answer:
Kc = 3.1x10²
Explanation:
At equilibrium, the velocity of product formation is equal to the velocity of reactants formation. For a generic reaction, the equilibrium constant (Kc) is:
aA + bB ⇄ cC + dD
![Kc = \frac{[C]^c*[D]^d}{[A]^a*[B]^b}](https://tex.z-dn.net/?f=Kc%20%3D%20%5Cfrac%7B%5BC%5D%5Ec%2A%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%2A%5BB%5D%5Eb%7D)
Where [X] is the molar concentration of X, and the solid substances are not considered (because it's activity is 1, for the other substances, the activity is substituted for the molar concentration, which forms the equation above).
For the reaction given, let's make an equilibrium chart:
Fe³⁺(aq) + SCN⁻(aq) ⇄ FeSCN²⁺(aq)
1.1*10⁻³ 8.2*10⁻⁴ 0 <em> Initial</em>
-x -x +x <em>Reacts</em> (stoichiometry is 1:1:1)
1.1*10⁻³ -x 8.2*10⁻⁴ -x x <em> Equilibrium</em>
x = 1.8*10⁻⁴ M, so the molar concentrations at equilibrium are:
[Fe⁺³] = 1.1*10⁻³ - 1.8*10⁻⁴ = 9.2*10⁻⁴ M
[SCN⁻] = 8.2*10⁻⁴ - 1.8*10⁻⁴ = 6.4*10⁻⁴ M
[FeSCN⁺²] = 1.8*10⁻⁴ M
Kc = [FeSCN⁺²]/([Fe⁺³]*[SCN⁻])
Kc = (1.8*10⁻⁴)/(9.2*10⁻⁴*6.4*10⁻⁴)
Kc = 306 = 3.1x10²
5.4 x 10²³ molecules
Explanation:
Given parameter
Volume of gas = 20L
Condition of reaction = STP
Unknown:
number of molecules
Solution:
The number of molecules of a substance is given by;
Number of molecules = Number of moles x avogadro's constant
Number of moles at stp = 
Number of moles of SO₂ = 
= 0.893mole
Number of molecules = 0.893 x 6.02 x 10²³ = 5.4 x 10²³ molecules
learn more:
Number of molecules brainly.com/question/10818009
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Answer:
The base layer of the shirt ( ORIGINAL COLOR) before dyed white was most likely yellow so the bleach lightened the colors to their original form
Explanation:
Answer:
25.0 mol O₂ are required in the second reaction
Explanation:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
4NH₃ (g) + 5O₂ (g) → 4NO (g) + 6 H₂O(l)
Molar ratio in first reaction is 1:2
For every mol of N₂. I make 2 moles of ammonia. If I have 20 moles of N₂, i'm going to get, 40 moles of ammonia.
In the second reaction, molar ratio between products is 4:5.
If I obtained 40 moles of ammonia in first step, let's prepare the rule of three.
4 moles of ammonia react with 5 moles of O₂
40 moles of ammonia react with ( 40.5) /4 = 25moles
<u>Answer:</u>
2.07 grams
<u>Explanation:</u>
We know that the molecular mass of 
is 138.205 grams.
In order to find out how many grams we need to make 200 mL having a potassium ion concentration of 0.150, we need to find the number of moles first.
M = moles / liters
0.150 = x / 0.200
x = 0.03 moles
Since there are 2 potassium atoms in each molecule of so we will divide this number by half and multiply it by the molecular mass.
0.03/2 = 0.015 moles
Mass of needed = 0.015 × 138.205 = 2.07 grams
