What is the longest wavelength of radiation that possesses the necessary energy to break the o-o bond?
1 answer:
Answer:
The longest wavelength of radiation is 241nm and it lies in ultraviolet region.
Explanation:
The minimum energy required to break o-o bond is 495kJ/mole.
The photon does not have mass and the energy of the single photon depends entirely on the wavelength and is given by
e =hc/λ
where, h is the Planck constant,
c is the speed of light
e is the energy of photon
λ is the wavelength
From the Planck formula we can understand that energy of the photon is quantized.
E = e.Nₐ
e = E/Nₐ = = 8.22*10⁻¹⁹ J/photon
λ = hc/E=
λ = 2.41*10⁻⁷ m = 241 nm
The longest wavelength of radiation is 241nm and it lies in ultraviolet region.
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Answer:
(a) t = 1.14 s
(b) h = 0.82 m
(c) vf = 7.17 m/s
Explanation:
(b)
Considering the upward motion, we apply the third equation of motion:
where,
g = - 9.8 m/s² (-ve sign for upward motion)
h = max height reached = ?
vf = final speed = 0 m/s
vi = initial speed = 4 m/s
Therefore,
<u>h = 0.82 m</u>
Now, for the time in air during upward motion we use first equation of motion:
(c)
Now we will consider the downward motion and use the third equation of motion:
where,
h = total height = 0.82 m + 1.8 m = 2.62 m
vi = initial speed = 0 m/s
g = 9.8 m/s²
vf = final speed = ?
Therefore,
<u>vf = 7.17 m/s</u>
Now, for the time in air during downward motion we use the first equation of motion:
(a)
Total Time of Flight = t = t₁ + t₂
t = 0.41 s + 0.73 s
<u>t = 1.14 s</u>
The gravitational potential energy U is defined as the product of mass m, the acceleration of gravity g and the height of object h.
We do not have the mass of the hiker. But we know that its W weight is:
Where
So:
.
So:
J
The hiker has gained 30,000 J of energy