Answer:
0.58 L
Explanation:
For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.
(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2
Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.
(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
Consider our givens:
P_1 = 110atm
T_1 = 303K
V_1 = 2L
P_2 = 440atm
T_2 = 353K
Now we simply plug in these values to the equation to find the new volume, V_2.
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
(110atm * 2L) * 353K / (303K * 440atm) = V_2
77660 atm*L*K / 133320 K*atm = V_2
0.583 L = V_2
Hence, the new volume is 0.583 L.
Cheers.
The answer is behaviorism !! <3
<span>
Plan: Use Q = m · c · ΔT three times. Hot casting cools ΔT_hot = 500°C -
Tf. Cold water and steel tank heat ΔT_cold = Tf - 25°C. Set Q from hot
casting cooling = Q from cold tank heating.
here
m_cast · c_steel · ΔT_hot = (m_tank · c_steel + m_water · c_water) · ΔT_cold
m_cast · c_steel · (500°C - Tf) = (m_tank · c_steel + m_water · c_water) · (Tf - 25°C)
2.5 kg · 0.50 kJ/(kg K°) · (500°C - Tf) = (5 kg· 0.50 kJ/(kg K°) + 40 kg· 4.18 kJ/(kg K°)) · (Tf - 25°C)
Solve for Tf, remember that K° = C° (i.e. for ΔT's) </span>
Answer:
4.99 mg of vitamin C are in the beaker.
Explanation:
Given that,
Weight of vitamin = 0.0499 g
Molar mass = 176.124 g/mol
Weight of water = 100.0 ml
We need to calculate the mg of vitamin C in the beaker
We dissolve 0.0499 g vitamin C in water to from 100.0 ml solution.
100 ml solution contain 49.9 mg vitamin C
Now, we take 10 ml of this vitamin C solution in breaker
Since, 100 ml solution =49.9 mg vitamin C
Therefore,
Hence, 4.99 mg of vitamin C are in the beaker.
