Answer:
0.07°C
Explanation:
<u>solution:</u>
the speed of a sound in water is<u>:</u>
v(T)=1480+4(T-4°C)
<u>at 4°C the travel time is:</u>
t(4◦C) = (
7600 × 103 m
)
/ (1480 m/s) = 5202.7 s
<u>5°C, the travel time is:</u>
t(5◦C) = (
7600 × 103 m
)
/ (1484 m/s) = 5188.7 s
<u>one degree C corresponds to a ∆t of 14 s so temperature difference is:</u>
ΔT=1 s/14 s=0.07◦C
Answer:
i can't click the answer bottom but the answer is "17th to 18th century" i hope this helps
To solve this problem we will apply the concepts related to load balancing. We will begin by defining what charges are acting inside and which charges are placed outside.
PART A)
The charge of the conducting shell is distributed only on its external surface. The point charge induces a negative charge on the inner surface of the conducting shell:
. This is the total charge on the inner surface of the conducting shell.
PART B)
The positive charge (of the same value) on the external surface of the conducting shell is:

The driver's net load is distributed through its outer surface. When inducing the new load, the total external load will be given by,



So when making structures you have to have squares rectangles right and a triangle and another triangle equals a square so thats all there is to it