Answer:
mass*velocity=1.5*10^4 * 15
= 22.5*10^4
<h3>a. The impulse</h3>
The impulse is 100.0 Ns
The impulse I = Ft where
- F =average force = 50.0 N and
- t = time = 2.0 s
Substituting these values into the equation, we have
I = Ft
I = 50.0 N × 2.0 s
I = 100.0 Ns
The impulse is 100.0 Ns
<h3>b. Change in momentum</h3>
The change in momentum is 100 kgm/s
Since change in momentum Δp = I where I = impulse.
Since I = 100.0 Ns,
Substituting this into the equation, we have
Δp = I
= 100.0 Ns
= 100 kgm/s
The change in momentum is 100 kgm/s
<h3>c. Mass's change in velocity</h3>
The change in velocity is 25.0 m/s
Since change in momentum Δp = mΔv where
- m = mass = 4.0 kg and
- Δv = change in velocity.
Making Δv subject of the formula, we have
Δv = Δp/m
Substituting the values of the variables into the equation, we have
Δv = Δp/m
Δv = 100.0 kgm/s/4.0 kg
Δv = 25.0 m/s
The change in velocity is 25.0 m/s
Learn more about impulse here:
brainly.com/question/25700778
Answer:
Displacement is the shortest distance from your initial position to your final position. Therefore, displacement is a measurement of distance and not an "end-point."
Answer:
The easiest way to do this is to realize that the time to fall is the same as the rise time (conservation of energy can easily verify this)
S = 1/2 g t^2 time to fall 2.5 m
t = (5 / 9.8)^1.2 = .714 sec time in air
v = a t = 9.8 * .714 = 7 m/s initial vertical speed
Check:
S = v t - 1/2 g t^2 where v is the initial vertical speed
S = 7 * .714 - 4.9 * .714^2 = 2.5 m total vertical distance traveled
The answer is directed northward. The acceleration will be negative, since the car is decelerating. Thus the power that is slowing it down must be performing in the opposite direction to that which the car is traveling. Or in other words, when speed is lessening, acceleration is in the opposed direction to velocity. The change is CONTRASTING the velocity and so it slows it down.
