If you have a 200g sample of a radioactive isotope that has a half life of 50 years, hc
1 answer:
Answer:
The correct option is;
a. 12.5 g
Explanation:
The given parameters are;
The initial mass of the radioactive substance = 200 g
The half life of the radioactive substance = 50 years
The time duration for the disintegration = 200 years
The formula for half life is given as follows;
Where:
N(t) = Quantity of the remaining substance
N₀ = Initial radioactive substance quantity = 200 g
t = Time duration = 200 years
= Half life of the radioactive substance 50 years
Therefore, we have;
Therefore, at the end of 200 years, the quantity left = 12.5 g.
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A) Net force in component form:
B) Magnitude of the net force: 316.2, direction:
Explanation:
A)
The three forces given in this problem are:
The three forces are given in component form, where the components with unit vector i is the component along the x-direction, while the components with unit vector j is the component along the y-direction.
In order to find the net force in component form, we just need to add the components of the three forces along each direction. Therefore:
- Along the x-direction:
- Along the y-direction:
So, the net force in component form is
B)
The magnitude of a vector F is given by Pythagorean's theorem:
where in this problem,
is the x-component
is the y-component
Substituting,
The direction instead is given by
where the negative sign means the direction is below the positive x-axis.
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