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Elina [12.6K]
3 years ago
10

If you have a 200g sample of a radioactive isotope that has a half life of 50 years, hc

Physics
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

The correct option is;

a. 12.5 g

Explanation:

The given parameters are;

The initial mass of the radioactive substance = 200 g

The half life of the radioactive substance = 50 years

The time duration for the disintegration = 200 years

The formula for half life is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}

Where:

N(t) = Quantity of the remaining substance

N₀ = Initial radioactive substance quantity  = 200 g

t = Time duration  = 200 years

 

t_{1/2} = Half life of the radioactive substance  50 years

Therefore, we have;

N(t) =200 \times \left (\dfrac{1}{2} \right )^{\dfrac{200}{50} } =200 \times \left (\dfrac{1}{2} \right )^4 = 12.5 \ g

Therefore, at the end of 200 years, the quantity left = 12.5 g.

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During a particular thunderstorm, the electric potential difference between a cloud and the ground is vcloud - vground = 3.50 10
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