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3 years ago

A amusement park moves riders in a circle at a rate of 6.0m/s if the radius is 9.0 meters what is the acceleration of the ride

Physics

1 answer:

oksano4ka [1.4K]3 years ago

4 0

Centripetal acceleration is (speed-squared) / (radius)

CA = (6 m/s)² / (9 m)

CA = (36 m²/s²) / (9 m)

CA = (36/9) (m²/m·s²)

<em>Centripetal acceleration = 4 m/s²</em>

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29.

Yuki888 [10]

Answer:

47.415 km .

Explanation:

We are given;

Time taken is 1.45 hours
Average speed of the bicycle is 32.7 Km/hr

We are supposed to work out for the distance;

We know that speed is the rate of change in distance given by;

Speed = Distance/time

Rearranging the formula, we can get distance;

Distance = Speed × time

In this case;

Distance = 32.7 km/hr × 1.45 hours

= 47.415 km .

Thus, the bicyclist travels for a distance of 47.415 km at the average speed of 32.7 km/hr.

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3 years ago

Starting from one oasis, a camel walks 25 km in a direction 30° south of west and then walks 30 km toward the north to a second

shepuryov [24]

Answer:

distance between both oasis ( 1 and 2) is 27.83 Km

Explanation:

let d is the distance between oasis1 and oasis 2

from figure

OC = 25cos 30

OE = 25sin30

OE = CD

Therefore BC = 30-25sin30

distance between both oasis ( 1 and 2) is calculated by using phytogoras theorem

in $\Delta BCO$

$OB^2 = BC^2 + OC^2$

PUTTING ALL VALUE IN ABOVE EQUATION

$d^2 = 930-25sin30)^2 + (25cos30)^2$

$d^2 = 775$

d = 27.83 Km

distance between both oasis ( 1 and 2) is 27.83 Km

3 0

3 years ago

A bird has kinetic energy of 3 J and the potential energy of 25 J what is the mechanical energy of the bird 3 J Because mechanic

tiny-mole [99]

Answer:

The total mechanical energy of the bird is, E = 28 J

Explanation:

The total mechanical energy of the system is the sum of the potential and kinetic energy of the system.

When a bird is flying at a certain height from the ground, it posses partial potential and kinetic energy.

The total energy,

E = P.E + K.E

P.E = mgh J

K.E = ½ mv²

The total mechanical energy of the bird at any instant of time is equal to its potential and kinetic energy.

Hence, the mechanical energy of the bird is, E = 25 J

3 0

4 years ago

They want a mixture of 150 grams of water at 60 degrees Celsius, using hot water at 90 degrees Celsius and cold water at 14 degr

Gnesinka [82]

Answer:

Explanation:

Here,

Final mass(m)=150g

Final Temperature(t)=60°C

Temperature of hot water(t1)=90C

Temperature of cold water(t2)=14C

Let the grams of water to be used per face be m1 grams and (150-m1) grams for hot and cold water respectively.

We know that,

Heat lost by hot body=Heat gained by cold body

or, m1 s1 Δt1=m2 s2 Δt2

or, m1 (t1-t)=(150-m1) (t-t2) [∵s1=s2, SHC of water is taken to be same]

or, m1 (90-60)=(150-m1) (60-14)

or, 30m1=6900-46m1

or, 76m1=6900

∴m1=90.79g

(150-m1)=59.21g

Hence, 90.79g and 59.21 g hot and cold water must be used respectively.

6 0

3 years ago

A person whose weight is 5.20 3 102 N is being pulled up vertically by a rope from the bottom of a cave that is 35.1 m deep. The

kodGreya [7K]

Answer:

It is given that the weight of the person is 102 N

We have the force that shall be needed to being the man out in minimum amount of time shall correspond to the maximum tension that can be developed

Thus using Newton's second law we obtain the acceleration that the man shall attain

$\sum F_{ext}=m\overrightarrow{a}\\\\T-W=ma\\\\\therefore a=\frac{T_{max}-W}{\frac{W}{g}}\\\\a_{max}=\frac{569-102}{\frac{102}{9.81}}=44.9m/s^{2}$

Now using second equation of kinematics to obtain time 't' we get

$t=\sqrt{\frac{2s}{g}}\\\\t=\sqrt{\frac{2\times 35.1}{44.9}}=1.25secs$

3 0

3 years ago