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Romashka [77]
3 years ago
10

A amusement park moves riders in a circle at a rate of 6.0m/s if the radius is 9.0 meters what is the acceleration of the ride

Physics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

Centripetal acceleration is (speed-squared) / (radius)

CA = (6 m/s)² / (9 m)

CA = (36 m²/s²) / (9 m)

CA = (36/9) (m²/m·s²)

<em>Centripetal acceleration = 4 m/s²</em>

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Answer:

Waves: "The phenomenon in which any number of particles or the energy packets that originates from a transmitter  travels in a direction and it is somehow directed towards a receiver end is called as waves."

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I hope this helps!!

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A ball is thrown up with a speed of 15m/s. How high will it go before it begins to fall? ( g = 10m/s2 )
LekaFEV [45]

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Height is 11.25m

Explanation:

<u>Given the following data;</u>

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To find the height, we would use the third equation of motion;

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
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V^{2} = U^{2} + 2aS

<em>Making S the subject, we have;</em>

S = \frac {V^{2} - U^{2}}{2a}

But a = g = 10m/s²

<em>Substituting into the equation, we have;</em>

S = \frac {15^{2} - 0^{2}}{2*10}

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S = \frac {225}{20}

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