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USPshnik [31]
3 years ago
13

Lab report of experimrnt to find the series resonance of acceptor circuit and parallel resonance of rejector circuit in RLC?

Physics
1 answer:
sammy [17]3 years ago
5 0

Answer:

afgiknvdeyiknvxwtuinvdruincdyukn

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Which object experiences the greatest gravitational force? A)car B)fire truck C)plane D)human
Svetlanka [38]

Answer: C Plane

Explanation: According to Newton's law, gravitational force is proportional to the product of masses and inversely proportional to the square of distance between them.

Gravitational force depends on mass. The bigger the mass, the more the magnitude of the gravitational force. Since plane is assume to have the highest mass in the options, we can therefore conclude that plane will experience the highest gravitational force.

3 0
3 years ago
What benefits does preforming this investigation in the physical world have over the computer simulation?
mezya [45]

Explanation:

Can be safer and cheaper than the real world. Able to test a product or system works before building it. Can use it to find unexpected problems. Can speed things up or slow them down to see changes over long or short periods of time.

.

.

.

.

3 0
3 years ago
The central star of a planetary nebula emits ultraviolet light with wavelength 104nm. This light passes through a diffraction gr
Gala2k [10]

Answer: 31.33 degrees

Explanation:

The diffraction angles \theta_{n} when we have a slit divided into n parts are obtained by  the following equation:

dsin\theta_{n}=n\lambda   (1)

Where:

d is the width of the slit

\lambda  is the wavelength of the light

n is an integer different from zero.

Now, the first-order diffraction angle is given when n=1, hence equation (1) becomes:

dsin\theta_{1}=\lambda   (2)

Now we have to find the value of \theta_{1}:

sin\theta_{1}=\frac{\lambda}{d}  

\theta_{1}=arcsin(\frac{\lambda}{d})   (3)

We know:

\lambda=104nm=104(10)^{-9}m

In addition we are told the diffraction grating has 5000 slits per mm, this means:

d=\frac{1mm}{5000}=\frac{1(10)^{-3}m}{5000}

Substituting the known values in (3):

\theta_{1}=arcsin(\frac{104(10)^{-9}m}{\frac{1(10)^{-3}m}{5000}})

\theta_{1}=arcsin(0.52)

<u>Finally:</u>

\theta_{1}=31.33\º >>>This is the first-order diffraction angle

4 0
3 years ago
A car travelling at 5.0 m/s starts to speed up. After 3.0 s its velocity has increased to 11 m/s. a) What is its acceleration? (
lions [1.4K]

initially, the car is traveling at 5.0 m/s.

so, we know acceleration for changing velocity is :

a = (v-v_{o})/t ..........(i)

where v is the final velocity

v_{o} is the initial velocity

t is the time taken to change velocity

Now, as per the question :

initial velocity, v_{o}=5.0 m/s

final velocity, v =11 m/s

time taken, t = 3 s

putting the values in equation (i),

a = ( 11-5 )/3

a = 2 m/s²

Therefore, a, after 3 s, is  <em>2 m/s².</em>

4 0
1 year ago
A well-insulated cup of water is too hot to make tea, so you mixed it with an equal amount of cool water to lower the temperatur
KonstantinChe [14]

Answer:The change in entropy of the total amount of water is negative as a result of the mixing.

Explanation:If you increase temperature, you increase entropy

Also More energy gives you greater entropy and randomness of the atoms.

4 0
3 years ago
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