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3 years ago

Which force is involved in kicking a ball? 1. Frictional force 2. Pushing force

Physics

2 answers:

FrozenT [24]3 years ago

7 0

Answer:

Pushing force

Explanation:

You technically push a ball when kicking it.

Alex3 years ago

5 0

she said she like me she wanna have lsex

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What is the only type of heat transfered by the sun to the earth convection, condensation, or radiation?

Debora [2.8K]

Radiation is the only one that works across the vacuum of space

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4 years ago

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A piece of wire is bent to form a circle with radius r. It has a steady current I flowing through it in a counterclockwise direc

dedylja [7]

Answer:

B=μ₀I/2r

Explanation:

Produced magnetic field due to an existing electric field through a coil or conductor can be explained by Biot-Savart Law. Formula for this law is:

dB=(μ₀I/4π.r²)dL

Here,

r=Radius of the loop

I and r are constants with respect to length L.

To convert linear displacement L into angular displacement Ф:

dL=r.dФ

So,

dB=(μ₀I/4π.r²)r.dФ

dB=(μ₀I/4π.r)dФ

Integrating both sides over the circle i.e. from 0 radians to 2π radians (360⁰), while the integration will apply only on dФ as all others are constants.

B=(μ₀I/4πr)(2π-0)

<u>B=(μ₀I/2r)</u>

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4 years ago

A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The

tensa zangetsu [6.8K]

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4 ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28 momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm

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3 years ago

When a surface is illuminated with electromagnetic radiation of wavelength 480 nm, the maximum kinetic energy of the emitted ele

algol [13]

Answer:

Max kinetic energy for 340 nm wavelength will be $2.238\times 10^{-19}j$

Explanation:

In first case wavelength of electromagnetic radiation $\lambda =480nm=480\times 10^{-9}m$

Plank's constant $h=6.6\times 10^{-34}J-s$

Maximum kinetic energy = 0.54 eV

Energy is given by $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{480\times 10^{-9}}=4.125\times 10^{-19}J$

We know that energy is given

$E=K_{MAX}+\Phi$ , here $\Phi$ is work function

So $4.125\times 10^{-19}=0.54\times 10^{-19}+\Phi$

$\Phi =3.585\times 10^{-19}J$

Now wavelength of second radiation = 340 nm

So energy $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{340\times 10^{-9}}=5.823\times 10^{-19}J$

So $K_{MAX}=5.823\times 10^{-19}-3.585\times 10^{-19}=2.238\times 10^{-19}j$

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4 years ago

A 2 block of ice is pushed along the ground with a constant 10 N force. Assuming there is no friction what is the acceleration o

Alex_Xolod [135]

Acceleration of block = net force/mass = 10/2 = 5 m/s²

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4 years ago