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Alex17521 [72]
3 years ago
15

A boat is able to move throught still water at 20m/s. It makes a round trip to a town 3.0km upstrea. If the river flows at 5m/s,

the time required for this round trip is
Physics
1 answer:
Kryger [21]3 years ago
8 0

Answer:

t=320s

Explanation:

Given Data

Boat speed=20 m/s

River flows=5 m/s

Total trip of distance d=3.0km = 3000m

To find

Total time taken

Solution

As

Velocity=distance/time\\time=distance/velocity\\

Here we have two conditions

First when boat moves upward and the river pushing back.then velocity is given as

velocity=20m/s-5m/s

velocity=15 m/s

Time for that velocity

t_{1} =distance/velocity\\t_{1}=\frac{3000m}{15m/s}\\ t_{1}=200s

Now for second condition when river flows and boat speed on same direction

velocity=20m/s+5m/s

velocity=25 m/s

Time taken for that velocity

t_{2}=distance/velocity\\t_{2}=\frac{3000m}{25m/s}\\ t_{2}=120m/s

Now the total time

t=t_{1}+t_{2}\\t=(200+120)s\\t=320s

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An object is 45.0 kg here on Earth. What is its mass on Jupiter if the acceleration
puteri [66]

Answer:

B. 45.0 kg

Explanation:

On earth the object has ;

Mass = 45 kg

acceleration = 9.81 m/s²

On Jupiter, acceleration is  24.79 m/s²

The mass of this object on Jupiter will be 45 kg. It will not change. Mass of an object will only change when you remove part of the object from it or add to it another part. The mass is the same on Earth and on Jupiter. However, due to increased acceleration on Jupiter , the weight will change/ increase because;

Weight = mass * acceleration

<u>On Earth </u>

Weight of the object will be : 45 *  9.81 = 441.45 kg

<u>On Jupiter</u>

Weight of the object will be : 45*24.79 =1115.55 kg

8 0
3 years ago
What is the best explanation of Moon phases?
Marizza181 [45]
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5 0
3 years ago
What is your hypothesis (or hypotheses) for this experiment?<br><br> (about Thermal Energy Transfer)
Nesterboy [21]

Answer:

I hypothesis that the motion involving the balls in the experiment were moving to create data.

Explanation:

I hope this helps!

3 0
3 years ago
What is the x-component of the force on the charge located at x = 8 cm given that q = 1.1 μC in N?
jonny [76]

Answer:

Answer is = 12.3 x 10^6 N

Explanation:

We need to calculate force on the charge which is in Newtons:

Formula is = K q1q2/r^2

k is constant depeneds on the permitivity of the medium and its value is 9x10^9 Nm^2/C^2

q1 and q2 are charges and r is the distance between these two charges so just by putting values we get F= 9x10^9 x 1.1x10^-6/(8x10^-2)^2 (we get the above answer in newton)

6 0
4 years ago
A 2,200 kg railway freight car coasts at 3.6 m/s underneath a grain terminal, which dumps grain directly down into the freight c
suter [353]

Answer:

m_2=2554.83\ kg

Explanation:

Given that,

Mass of the car, m_1=2200\ kg

Initial speed of the car, u=3.6\ m/s

Final speed of the car, v=3.1\ m/s

To find,

The maximum mass of grain that it can accept.

Solution,

We know that according to the law of conservation of momentum, the initial momentum is equal to the final momentum.

m_1u=m_2v

m_2=\dfrac{m_1u}{v}

m_2=\dfrac{2200\times 3.6}{3.1}

m_2=2554.83\ kg

Therefore, the maximum mass of grain that it can accept is 2554.83 kg. Hence, this is the required solution.

7 0
3 years ago
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