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Dafna11 [192]
2 years ago
11

The maximum static friction between a box and the table is 15.0N when the normal force on the box is 35.0N. What is the coeffici

ent of friction between the box and the table?
Physics
1 answer:
Marysya12 [62]2 years ago
6 0

Answer:

you are going through this week of x factor of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal

Explanation:

you are going through this week of x factor of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and technology practical pdf the new modal and F kisna of x and

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What is the mass of an object if a force of 2N and gives it an acceleration of 2 m/s2​
tino4ka555 [31]

Answer:

1kg

Explanation:

Use the formula

F=ma

m=F/a

m=2N/2m/s^2

m=1kg

6 0
2 years ago
During the time interval from 0.0 to 10.0 s, the position vector of a car on a road is given by x(t) = a + bt + ct2, with a = 17
Juli2301 [7.4K]

The car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.

<h3>Average velocity of the car</h3>

The average velocity of the car is calculated as follows;

x(t) = a + bt + ct2

v = dx/dt

v(t) = b + 2ct

v(0) = -10.1 m/s + 2(1.1)(0) = -10.1 m/s

v(10) = -10.1 + 2(1.1)(10) = 11.9 m/s

<h3>Average velocity</h3>

V = ¹/₂[v(0) + v(10)]

V = ¹/₂ (-10.1  + 11.9 )

V = 0.9 m/s

Thus, the car’s velocity as a function of time is b + 2ct and the car’s average velocity during this interval is 0.9 m/s.

Learn more about velocity here: brainly.com/question/4931057

#SPJ1

3 0
1 year ago
A uranium ion and an iron ion are separated by a distance of =61.10 nm. The uranium atom is singly ionized; the iron atom is dou
scoray [572]

Answer:

Explanation:

Charge on uranium ion = charge of a single electron

= 1.6 x 10⁻¹⁹ C

charge on doubly ionised iron atom = charge of 2 electron

= 2 x 1.6 x 10⁻¹⁹ C = 3.2 x 10⁻¹⁹ C

Let the required distance from uranium ion be d .

force on electron at distance d from uranium ion

= 9 x 10⁹ x 1.6 x 10⁻¹⁹ / r²

force on electron at distance 61.10 x 10⁻⁹ - r from iron  ion

= 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²

For equilibrium ,

9 x 10⁹ x 1.6 x 10⁻¹⁹ / r² = 9 x 10⁹ x 3.2 x 10⁻¹⁹ / (61.10 x 10⁻⁹ - r )²

2 d² = (61.10 x 10⁻⁹ - r )²

1.414 r = 61.10 x 10⁻⁹ - r

2.414 r = 61.10 x 10⁻⁹

r = 25.31 nm .

4 0
3 years ago
Which object would be the best insulator of electricity?
solniwko [45]

Answer:

a rubber band

Explanation:

hope this helps!

7 0
2 years ago
Read 2 more answers
PLEASE HELP!! ILL MARK BRAINLYEST!!
topjm [15]

Answer: True

Explanation:

Mass is the amount of matter in an object. Everything is made up of matter.

3 0
3 years ago
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