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pashok25 [27]
3 years ago
8

.5(x + 3) ^{2} " alt="x + 5 = 0.5(x + 3) ^{2} " align="absmiddle" class="latex-formula">
Physics
1 answer:
nikitadnepr [17]3 years ago
6 0
Solve for x over the real numbers = complete the square
x + 5 = 0.5 (x + 3)^2

0.5 (x + 3)^2 = 1/2 (x + 3)^2:
x + 5 = 1/2 (x + 3)^2

Expand out terms of the right hand side:
x + 5 = x^2/2 + 3 x + 9/2

Subtract x^2/2 + 3 x + 9/2 from both sides:
-x^2/2 - 2 x + 1/2 = 0

Multiply both sides by -2:
x^2 + 4 x - 1 = 0

Add 1 to both sides:
x^2 + 4 x = 1

Add 4 to both sides:
x^2 + 4 x + 4 = 5

Write the left hand side as a square:
(x + 2)^2 = 5

Take the square root of both sides:
x + 2 = sqrt(5) or x + 2 = -sqrt(5)

Subtract 2 from both sides:
x = sqrt(5) - 2 or x + 2 = -sqrt(5)

Subtract 2 from both sides:
Answer:  x = sqrt(5) - 2 or x = -2 - sqrt(5)
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Answer:

very smooth and polished glass mirror

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3 years ago
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vichka [17]
What is the definition of newton
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3 years ago
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Rudiy27
Okay so yeah u have to minus then subtract then decide it it’s a method i was taught to do
5 0
3 years ago
If a girl carries groceries up a flight of stairs, is she doing work on the groceries? Explain.​
nikdorinn [45]

Answer:

Explanation:

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4 0
3 years ago
Suppose that you are standing on a train accelerating at 0.20g. What minimum coefficient of static friction must exist between y
Ilia_Sergeevich [38]
Acceleration = (0.2 x g) = 1.96m/sec^2. 
<span>Accelerating force on 1kg. = (ma) = 1.96N. </span>
<span>1kg. has a weight (normal force) of 9.8N. </span>
<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>

<span>Coefficient is a ratio, so holds true for any value of mass to find accelerating force acting. </span>
<span>e.g. 75kg = (75 x g) = 735N. </span>
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5 0
4 years ago
Read 2 more answers
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