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pashok25 [27]
3 years ago
8

.5(x + 3) ^{2} " alt="x + 5 = 0.5(x + 3) ^{2} " align="absmiddle" class="latex-formula">
Physics
1 answer:
nikitadnepr [17]3 years ago
6 0
Solve for x over the real numbers = complete the square
x + 5 = 0.5 (x + 3)^2

0.5 (x + 3)^2 = 1/2 (x + 3)^2:
x + 5 = 1/2 (x + 3)^2

Expand out terms of the right hand side:
x + 5 = x^2/2 + 3 x + 9/2

Subtract x^2/2 + 3 x + 9/2 from both sides:
-x^2/2 - 2 x + 1/2 = 0

Multiply both sides by -2:
x^2 + 4 x - 1 = 0

Add 1 to both sides:
x^2 + 4 x = 1

Add 4 to both sides:
x^2 + 4 x + 4 = 5

Write the left hand side as a square:
(x + 2)^2 = 5

Take the square root of both sides:
x + 2 = sqrt(5) or x + 2 = -sqrt(5)

Subtract 2 from both sides:
x = sqrt(5) - 2 or x + 2 = -sqrt(5)

Subtract 2 from both sides:
Answer:  x = sqrt(5) - 2 or x = -2 - sqrt(5)
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A sample of a gas has a volume of 639 cm3 when the pressure is 75.9 kPa. What is the volume of the gas when the pressure is incr
const2013 [10]

Answer:

388 cm^3

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

pV=const.

which can also be rewritten as

p_1 V_1 = p_2 V_2

In our case, we have:

p_1 = 75.9 kPa is the initial pressure

V_1 = 639 cm^3 is the initial volume

p_2 = 125 kPa is the final pressure

Solving for V2, we find the final volume:

v_2 = \frac{p_1 V_1}{p_2}=\frac{(75.9)(639)}{125}=388 cm^3

7 0
4 years ago
One block rests upon a horizontal surface. A second identical block rests upon the first one. The coefficient of static friction
Sophie [7]

Answer:

F = 156.3 N

Explanation:

Let's start with the top block, apply Newton's second law

         F - fr = 0

         F = fr

         fr = 52.1 N

Now we can work  with the bottom block

In this case we have two friction forces, one between the two blocks and the other between the block and the surface. In the exercise, indicate that the two friction coefficients are equal

we apply Newton's second law

Y axis

        N - W₁ -W₂ = 0

        N = W₁ + W₂

as the two blocks are identical

        N = 2W

X axis

        F - fr₁ - fr₂ = 0

        F = fr₁ + fr₂

indicates that the lower block is moving below block 1, therefore the upper friction force is

          fr₁ = 52.1 N

          fr₁ = μ N

a

s the normal in the lower block of twice the friction force is

          fr₂ = μ 2N

          fr₂ = 2 μ N

          fr₂ = 2 fr₁

we substitute

          F = fr₁ + 2 fr₁

          F = 3 fr₁

          F = 3  52.1

          F = 156.3 N

7 0
3 years ago
The object represented by this graph is moving
Vinil7 [7]

The object represented by this graph is moving toward the origin at constant velocity.

Option 3.

<u>Explanation:</u>

In the figure, x-axis is representing increase in the time and y-axis is presenting increase in the distance from bottom to up. But the line in the graph which is plotted is decreasing from high distance to small distance with increase in time. So this indicates that as the time is increasing, the distance is decreasing.

And the object is moving toward the origin as the distance of the object motion is found to decrease with increase of time as per the graph. But the slope of the graph is found to be almost constant, this indicates that the velocity of the object is constant. Thus, the object represented by this graph is moving toward the origin at constant velocity.

4 0
3 years ago
Read 2 more answers
2 QUESTIONS HELP PLZ...:/
algol [13]
The first one is: head
Second one is: 10 trillion km
5 0
4 years ago
I need help with this problem :(​
Reil [10]

Answer:

it tells you that the speed increases until about 20 seconds then keeps a steady pace for 20 seconds then the speed drops and stops at 55 seconds in the process.

7 0
3 years ago
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