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diamong [38]
3 years ago
9

3. What is the acceleration of a 10 kg mass pushed by a 5 N force?

Physics
2 answers:
Lesechka [4]3 years ago
7 0

Answer:

\frac{1}{2}  \frac{m}{s^2}

Explanation:

Recall the equation F = ma. We want to find a, and we already know F and m, so we can plug those in. 5N = 10kg \cdot a -> a = 5N/10kg = \frac{1}{2}  \frac{m}{s^2}

insens350 [35]3 years ago
5 0

Answer:

F=ma

Plug it in:

5=10a

5/10=(10a)/10

.5m/s²=a

Explanation:

Brainliest?

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I think you meant to ask whether the body can have increasing velocity
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If the body's velocity is in the positive direction, then positive acceleration
means speeding up, and negative acceleration means slowing down.

BUT ... If the body's velocity is in the negative direction, then positive
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I know that's confusing. 

-- Take a piece of scratch paper, write a 'plus' sign at one edge and
a 'minus' sign at the other edge.  Those are the definitions of which
direction is positive and which direction is negative. 

-- Then sketch some cars ... one traveling in the positive direction, and
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. . . . . first push on the back of the car, in the direction it's moving;.
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3 0
3 years ago
What is 18 m/s north an example of?
Mkey [24]

Answer:

It is an example of velocity

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8 0
3 years ago
How much energy is required to move an electron through a potential difference of
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3 0
3 years ago
Whar are codes of behavior in the gym that should be followed​
Sunny_sXe [5.5K]

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5 0
3 years ago
A uniformly charged, straight filament 5.10 m in length has a total positive charge of 2.00 µC. An uncharged cardboard cylinder
Ratling [72]

Answer:

70509.8039216 N/C

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

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l = Length of filament = 5.1 m

r = Radius of cylinder = 10 cm

\lambda=\dfrac{q}{l}

Electric field is given by

E=\dfrac{2k\lambda}{r}\\\Rightarrow E=\dfrac{2\times 8.99\times 10^9\times \dfrac{2\times 10^{-6}}{5.1}}{10\times 10^{-2}}\\\Rightarrow E=70509.8039216\ N/C

The electric field at the surface of the cylinder is 70509.8039216 N/C

7 0
3 years ago
Read 2 more answers
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