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diamong [38]
3 years ago
9

3. What is the acceleration of a 10 kg mass pushed by a 5 N force?

Physics
2 answers:
Lesechka [4]3 years ago
7 0

Answer:

\frac{1}{2}  \frac{m}{s^2}

Explanation:

Recall the equation F = ma. We want to find a, and we already know F and m, so we can plug those in. 5N = 10kg \cdot a -> a = 5N/10kg = \frac{1}{2}  \frac{m}{s^2}

insens350 [35]3 years ago
5 0

Answer:

F=ma

Plug it in:

5=10a

5/10=(10a)/10

.5m/s²=a

Explanation:

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A 0.025-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 150 N/m.
devlian [24]

Answer:

K=0.4368J

Explanation:

The mechanical energy will be the sum of the elastic energy and the kinetic energy of the block: E=U+K. Their formulas are U=\frac{k\Delta x^2}{2} and K=\frac{mv^2}{2} for any point in the movement (although E must remain constant since the movement is frictionless), where k is the spring constant, \Delta x the displacement, m the mass of the block and v its velocity.

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Since mechanical energy is conserved, the mechanical energy at that point must be equal also to the mechanical energy at the point asked, which we will call P (when the displacement is x_P=0.024m), so we will have:

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