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Art [367]
3 years ago
7

In March 2007, Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours. You wonder

whether the amount UMSL students study is different from this 14.6 hour benchmark. Set up the hypotheses used in this situation.
Mathematics
1 answer:
Rasek [7]3 years ago
5 0

Answer:

The hypotheses used in this situation

H_0:\mu = 14.6

H_a:\mu \neq 14.6

Step-by-step explanation:

We are given that  Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.

Mean = \mu = 14.6

Claim : The amount UMSL students study is different from this 14.6 hour benchmark.

The hypotheses used in this situation

H_0:\mu = 14.6

H_a:\mu \neq 14.6

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Please response ASAP!<br><br> 2+3=<br> 9+2=<br> 0+1=<br> 7+4=
Stolb23 [73]

2+3=5

9+2=11

0+1=1

7+4=11

3 0
3 years ago
Read 2 more answers
W over 3&lt; 1 or 3w+5&gt;11
s344n2d4d5 [400]

Step-by-step explanation:

\dfrac{w}{3}6\qquad\text{divide both sides by 3}\\\\\dfrac{3w}{3}>\dfrac{6}{3}\\\\w>2\\\\

\text{If is}\ \bold{OR},\ \text{then}:\\\\w2\Rightarrow w\in\mathbb{R}\ /\text{any real number/}\\\\\text{If there is a mistake, and it should be}\ \bold{AND},\ \text{then}:\\\\w2\Rightarrow 2

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3 years ago
Binghamton scholars were counting around the room. The first scholar said "672,"
Gala2k [10]

Answer:

792. each time you add ten

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2 years ago
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You row a canoe x miles per hour down a river for 20 minutes. On the return trip, you travel 1 mile per hour slower. The return
ozzi

Answer:

Total Distance = 2 miles

Step-by-step explanation:

We know D = RT where

D is distance

R is rate (speed)

T is time

First Leg:

Rate = x mph

Time = 20/60 = 1/3 hour

Hence, D = RT, Distance = x * 1/3 = x/3 miles

Second Leg:

Rate = x - 1

Time = 30/60 = 1/2 hour

Distance = (x - 1) * 1/2 = (x-1)/2

Total distance is the sum of both the legs, hence,

Total distance = \frac{x}{3}+\frac{x-1}{2}=\frac{2x+3(x-1)}{6}=\frac{2x+3x-3}{6}=\frac{5x-3}{6} miles

Since both the distance are equal we can equate and solve:

\frac{x}{3}=\frac{x-1}{2}\\2x=3x-3\\x=3

Plugging this x = 3 into the total distance expression, we get:

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Total distance, 2 miles

5 0
3 years ago
A ball is thrown upward from the top of a 40 foot high building at a speed of 80 feet per second. The ball's height above
tekilochka [14]

it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.

Let h(t) represent the height of the ball at time t.

Given that the height is given by:

h(t) = -16t² + 80t + 40

1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:

40 = -16t² + 80t + 40

16t² - 80t = 0

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t = 0 or t = 5

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2) The maximum height is at h'(t) = 0,

h'(t) = -32t + 80

-32t + 80 = 0

32t = 80

t = 2.5

It takes 2.5 seconds to reach maximum height.

Find out more at: brainly.com/question/11535666

5 0
2 years ago
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