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Art [367]
3 years ago
7

In March 2007, Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours. You wonder

whether the amount UMSL students study is different from this 14.6 hour benchmark. Set up the hypotheses used in this situation.
Mathematics
1 answer:
Rasek [7]3 years ago
5 0

Answer:

The hypotheses used in this situation

H_0:\mu = 14.6

H_a:\mu \neq 14.6

Step-by-step explanation:

We are given that  Business Week reported that at the top 50 business schools, students studied an average of 14.6 hours.

Mean = \mu = 14.6

Claim : The amount UMSL students study is different from this 14.6 hour benchmark.

The hypotheses used in this situation

H_0:\mu = 14.6

H_a:\mu \neq 14.6

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A box of cereal contains 512 grams of sugar
sasho [114]
Then? You didn't type the full question
3 0
3 years ago
If f(x) = 2x2 +5/(x-2), complete the following statement:
faust18 [17]

For this case we have the following function:

f (x) = 2x ^ 2 + \frac {5} {x-2}

By definition, we have that the domain of a function is given by all the values for which the function is defined. The given function is not defined when the denominator is zero.

So:

x-2 = 0\\x = 2

Thus, the function is not defined at x = 2.

The domain is given by all real numbers except 2.

Answer:

The domain is given by all real numbers except 2.

3 0
3 years ago
Suppose an opaque jar contains 3 red marbles and 10 green marbles. The following exercise refers to the experiment of picking tw
kow [346]

Answer:

\frac{5}{13}

Step-by-step explanation:

Given,

Red marbles = 3,

Green marbles = 10,

So, the total marbles = 3 + 10 = 13,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Since, here replacement is not allowed,

Thus, the probability of getting a green marble and a red marble

= first red and second green + first green second red

=\frac{3}{13}\times \frac{10}{12}+\frac{10}{13}\times \frac{3}{12}

=2\times \frac{3}{13}\times \frac{10}{12}

=\frac{30}{78}

=\frac{5}{13}

Note : The probability of getting a green marble first and a red marble second

= \frac{10}{13}\times \frac{3}{12}

=\frac{30}{156}

=\frac{5}{26}

4 0
4 years ago
Please help me with all three! 25 Points!!
Gnoma [55]

a. 28 * 63

28 (60) + 28 (3) or 20 (60) +20 (3) + 8 (60) + 8 (3)

1680 + 84=1764     1200 / 60 +480 +24=1764


b. 17(59)

17 (50) + 17 (9)   or  10 (50) + 10 (9) + 7 (50) +7 (3)

850 + 153=1003         500 + 90 + 63 =1003


c.458 (15)

458 (10) +458 (5)   or  10 (400) + 10 (50) + 10 (8) + 5 (400) +5 (50) + 5 (8)

4580 +2290 = 6870       400 + 500 + 80 + 2000 + 250 + 40 = 6870

My work is kinda confusing but hope it helped

8 0
3 years ago
Find the angles please please
IceJOKER [234]
Angle BAC
cosφ⁻¹ = (10² + 17² - 11²)/(2*10*17) = 37.9 ≈ 38°
Angle ACB
cosφ⁻¹ = (10² + 11² - 17²)/(2*10*11) = 108.0°
Angle ABC
cosφ⁻¹ = (11² + 17² - 10²)/(2*11*17) = 34.0°
See you !
6 0
3 years ago
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