Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
Please check explanations
Step-by-step explanation:
Here, we have three types of equations and three plotted graphs
we have a quadratic equation
an exponential equation
and a linear equation
For a quadratic equation, we usually have a parabola
The first equation is quadratic and as such the first graph that is parabolic belongs to it
For an exponential equation, we usually have a graph that rises or falls before becoming flattened
The second equation represents an exponential equation so the second graph is for it
Lastly, we have a linear equation
A linear equation usually has a straight line graph
Thus, as we can see, the third graph represents the linear equation
Answer:
how much wood do you need
Answer:
(7−2)(3)(24−11)
=(5)(3)(24−11)
=15(24−11)
=(15)(13)
=195
Step-by-step explanation:
