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galina1969 [7]
3 years ago
7

How much must a woman weigh ( force) if the pressure she exerts while standing on one foot has an area of 0.6m squared exerts a

pressure of 16 Pa
​

Physics
1 answer:
lions [1.4K]3 years ago
4 0

Answer:

W = 9.6 N

Explanation:

Given that,

Area on 1 foot, A = 0.6 m²

Pressure, P = 16 Pa

The pressure is given by force acting per unit area. So,

P=\dfrac{F}{A}\\\\P=\dfrac{W}{A}\\\\W=16\times 0.6\\\\W=9.6\ N

So, the required weight is 9.6 N.

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The period and freqency of a wave are inversely related true or false​
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Which surface feature of the moon is characterized by mountainous areas?
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A 2 kg block is on a horizontal surface. A horizontal force is applied by a person to the block to pull it on the surface with a
Agata [3.3K]

Answer:

work done = 500 J

option e is correct

Explanation:

given data

mass = 2 kg

acceleration = 2 m/s

coefficient of kinetic friction = 0.3

block D = 50 m

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work

solution

we know that work done is

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here f is force and d is block i.e 50 m

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3 0
3 years ago
Suppose that a solid ball, a solid disk, and a hoop all have the same mass and the same radius. Each object is set rolling witho
8090 [49]

Answer:

Hoop will reach the maximum height

Explanation:

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They all  are rolled with similar initial speed v

by the law of conservation of energy we can write

K_{trans}+K_{rot}= P

for solid ball

[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{ball}\omega^2= mgh_{ball}

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now for solid disk

[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{disk}\omega^2= mgh_{disk}

putting I_{ball}=\frac{1}{2}mr^2 and \omega=\frac{v}{r} in the above equation and solving we get

h_{disk}= 0.076v^2

for hoop

[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{hoop}\omega^2= mgh_{hoop}

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h_{hook}= 0.10v^2

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3 years ago
What is simple machine?​
PolarNik [594]

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