Answer:
154 g
Explanation:
Step 1: Write the balanced decomposition equation
2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)
Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP
At STP, 1 mole of N₂ occupies 22.4 L.
79.5 L × 1 mol/22.4 L = 3.55 mol
Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂
The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.
Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃
The molar mass of NaN₃ is 65.01 g/mol.
2.37 mol × 65.01 g/mol = 154 g
Answer:
The answer would be C). All of the elements inside a period will always have the same amount of shells. Hope this helps!
Answer:
The density of ozone is 4.24.
Explanation:
The relation between the relative rate of diffusion and density is given by :
The given ratio of the relative rate of diffusion of ozone as compared to chlorine is 6:3.
Let the density of ozone is d₂.
So, the density of ozone is 4.24.
Extreme weather e.g. snow and cold weather. Another main contributing factor is that many places have a long dry season.
