The mass of cobalt (III) needed is
m = 5.2 L (0.42 mol/L) ( 93 g/mol)
m = 97.65 g
The volume of nitric acid needed is
V = 5.2 L (0.42 mol/L) (3 mol / 1 mol) (1000 mL/1.6 mol)
V = 1968.75 mL
The moles of water produced is
n = 5.2 L (0.42 mol/L) (3 mol / 1 mol)
n = 3.15 moles
Answer:
The same number of proteins in their nucleus.
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Explanation:
balance the equation ...HCl,Ba(OH) and BaCl2 are aqueous
know groups of the elements H 1+ ,Cl -,Ba 2+,OH-
write complete ionic eqution and eliminate spectator ions those appearing on both sides Cl and Ba
