How is a warm front formation diffrent from occlued front formation
1 answer:
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Answer:
True.
Explanation:
- Catalyst increases the rate of the reaction without affecting the equilibrium position.
- Catalyst increases the rate via lowering the activation energy of the reaction.
- This can occur via passing the reaction in alternative pathway (changing the mechanism).
- The activation energy is the difference in potential energies between the reactants and transition state (for the forward reaction) and it is the difference in potential energies between the products and transition state (for the reverse reaction).
- in the presence of a catalyst, the activation energy is lowered by lowering the energy of the transition state, which is the rate-determining step, catalysts reduce the required energy of activation to allow a reaction to proceed and, in the case of a reversible reaction, reach equilibrium more rapidly.
- with adding a catalyst, both the forward and reverse reaction rates will speed up equally, which allowing the system to reach equilibrium faster.
- Kindly, see the attached image.
Answer:
Explanation:
Here, we want to get the volume of the nitrogen gas at the lower temperature
From Charles' law, we know that volume and temperature (in Kelvin) are directly proportion
The mathematical relationship is:
Where:
V1 is the initial volume which is 410 L
V2 is the final volume which is unknown
T1 is the initial temperature which we will convert to Kelvin by adding 273.15 K, we have it as 61 + 273.15 = 334.15 K
T2 is the final temperature which we have to convert to Kelvin by adding it to 273.15K : We have that as -25 + 273.15 = 248.15 K
Substituting the values, we have it that: