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Lunna [17]
3 years ago
6

What do you mean by velocity ratio of a wheel and axle​

Physics
1 answer:
IgorC [24]3 years ago
5 0

Answer:

Explanation:

In wheel and axle. …with the system is the velocity ratio, or the ratio of the velocity (VF) with which the operator pulls the rope at F to the velocity at which the weight W is raised (VW). This ratio is equal to twice the radius of the large drum divided by the difference…

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Please help: 2.Le pluriel Questions
sp2606 [1]

1. bleus

2. rouges

3. petites

4. actifs

5. gross

Just add an -s to make it plural

8 0
2 years ago
A major league baseball has a mass of 0.145 kg.
galben [10]

The momentum of the ball when it hits the ground is 4.89 kg.m/s.

The given parameters;

  • <em>mass of the baseball, m = 0.145 kg</em>
  • <em>height of fall of the ball, h = 58 m</em>

The final velocity of the ball when it hits the ground is calculated as follows;

v_f ^2 = v_0^2 + 2gh\\\\v_f^2 = 0 + 2gh\\\\v_f^2 = 2gh\\\\v_f = \sqrt{2gh} \\\\v_f = \sqrt{2\times 9.8 \times 58}\\\\v_f = 33.72 \ m/s

The momentum of the ball when it hits the ground is calculated as follows;

P = mv

P = 0.145 x 33.72

P = 4.89 kg.m/s

Thus, the momentum of the ball when it hits the ground is 4.89 kg.m/s.

Learn more here:brainly.com/question/22035809

6 0
2 years ago
What acceleration does the force of earth's gravity peoduce
maksim [4K]
Near Earth's surface, gravitational acceleration is approximately 9.81 m/s2, which means that, ignoring the effects of air resistance, the speed of an object falling freely will increase by about 9.81 metres per second every second.
8 0
3 years ago
A team of engineering students is designing a catapult to launch a small ball at A so that it lands in the box. If it is known t
Murljashka [212]

Answer:

Explanation:

If the initial velocity is U

Then the horizontal component of the velocity is

Ux= Ucosθ

Then the range for a projectile is give as

R=Ux.t

Where t is the time of flight

The time of flight is given as

t=2USinθ/g

Therefore,

R=Ux.t

R=UCosθ.2USinθ/g

R=U^2×2SinθCosθ/g

Then, from trigonometric ratio

2SinθCosθ= Sin2θ

R=U^2Sin2θ/g

Given that θ=32° and g=9.81m/s^2

Then

R=U^2Sin2×32/9.81

R=U^2Sin64/9.81

R=0.0916U^2

Then, range is given by R=0.0916U^2

A=0.0916U^2.

T

The box is at a distance A from the point of projection. Then the range R=A

R=0.0916U^2

A=0.0916U^2

Then,

U^2=A/0.0916

U^2=10.915A

Then the initial velocity should be

U=√10.915A

U=3.3√A

8 0
3 years ago
A constant voltage of 12.00 V has been observed over a certain time interval across a 1.20 H inductor. The current through the i
kiruha [24]

Answer:

The time is 0.5 sec.

Explanation:

Given that,

Voltage V= 12.00 V

Inductance L= 1.20 H

Current = 3.00 A

Increases rate = 8.00 A

We need to calculate change in current

\Delta A = 8.00-3.00= 5.00\ A

We need to calculate the time interval

Using formula of inductor

V=L\dfrac{\Delta A}{\Delta t}

\Delta t =\dfrac{L\Delta A}{V}

Where, \Delta A = change in current

V = voltage

L = inductance

Put the value into the formula

\Delta t=\dfrac{1.20\times5.00}{12.00}

\Delta t=0.5\ sec

Hence, The time is 0.5 sec.

5 0
3 years ago
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