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3 years ago

Help mee plss its very urgent i need this before 11 pm est

Physics

2 answers:

dmitriy555 [2]3 years ago

6 0

Answer:

7. 2 kg

8. 0.5 kg

9. 4 kg

Explanation:

The equation is F=MA

where F is force in Newtons

M is mass in kg

A is acceleration in m/s^2

for each you substitute in the F and A, and you are finding M. Meaning you divide F by A.

M = F/A

6/3 = 2

6/12 = 0.5

20/5 = 4

Vera_Pavlovna [14]3 years ago

5 0

Answer:

Explanation:

m = 2 kg

m = 0.5 kg

m = 4 kg

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Compare the mass of block A, the mass of block B is:

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the answer would be b. it`s half as great

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3 years ago

Azurite is a mineral that contains 55.1% of copper. How many meter of copper wire with diameter of 0.0113 in can be produced fro

soldier1979 [14.2K]

Answer:

1402.73 m

Explanation:

Mass of Azurite=3.25 lb

Percent of copper in AZurite mineral=55.1%

Diameter of copper wire,d=0.0113 in

Radius of copper wire= $r=\frac{d}{2}=\frac{0.0113}{2}=0.00565 in=\frac{565}{100000}=\frac{565}{100}\times \frac{1}{1000}=5.65\times 10^{-3}in$

$\frac{1}{1000}=10^{-3}$

Density of copper= $\rho=8.96g/cm^3$

1 lb=454 g

3.25 lb= $3.25\times 454=1475.5 g$

Mass of Azurite= $1475.5 g$

Mass of copper= $\frac{55.1}{100}\times 1475.5=813 g$

Density= $\frac{Mass}{volume}$

Using the formula

$8.96=\frac{813}{volume\;of\;copper}$

Volume of copper wire= $\frac{813}{8.96}=90.7cm^3$

Radius of copper wire= $5.65\times 10^{-3}\times 2.54=14.35\times 10^{-3} cm$

1 in=2.54 cm

Volume of copper wire= $\pi r^2 h$

$\pi=3.14$

Using the formula

$90.7=3.14\times (14.35\times 10^{-3})^2\times h$

$h=\frac{90.7}{3.14\times (14.35\times 10^{-3})^2}$

$h=140273 cm$

1 m=100 cm

$h=\frac{140273}{100}=1402.73 m$

Hence, the length of copper wire required=1402.73 m

7 0

3 years ago

If some electrons are transferred from object A to object B,

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Answer: A. Object A will have a positive charge.

Explanation: If the number of protons and electrons are the same, their net charges cancel each other out, and you have a neutral charge. If electrons are transferred to another object, the amount of positive charge will outweigh the amount of negative charge. As a result, you are left with an overall positive charge in object A. Meanwhile, object B is now negative.

6 0

3 years ago

If the velocity of the incident charged particle were doubled, how would b have to change (keeping all other parameters constant

Paraphin [41]

If you double the velocity you would have to halve the magnetic field strength to keep the force on the particle the same and hence the trajectory.

F = qvB

6 0

3 years ago

A uniform steel rod has mass 0.300 kg and length 40.0 cmand is horizontal. A uniform sphere with radius 8.00 cm and mass 0.700 k

Brrunno [24]

Answer:

1.86 cm

Explanation:

The center of gravity of the combined object x = m₁x₁ + m₂x₂ + m₃x₃/m₁ + m₂ + m₃ where m₁ = mass of sphere on left end of rod = 0.700 kg, x₁ = distance of center of mass of sphere from left end of combined object = radius of sphere = 8.00 cm, m₂ = mass of rod = 0.300 kg, x₂ = distance of center of mass of rod from left end of combined object = diameter of sphere on left end + length of rod/2 = 16.00 cm + 40 cm/2 = 16.00 cm + 20 cm = 36 cm, m₃ = mass of sphere on right end of rod = 0.580 kg, x₃ = distance of center of mass of sphere from left end of combined object = length of rod + diameter of first sphere + radius of sphere = 40 cm + 16 cm + 6.00 cm = 62 cm

x = (m₁x₁ + m₂x₂ + m₃x₃)/m₁ + m₂ + m₃

Substituting the values of the variables into the equation, we have

x = 0.700 kg × 8.00 cm + 0.300 kg × 36 cm + 0.580 kg × 62 cm/(0.700 kg + 0.300 kg + 0.580 kg)

x = 5.6 kg cm + 10.8 kg cm + 35.96 kg cm/1.580 kg

x = 52.36 kgcm/1.580 kg

x = 33.14 cm

Since the center of the rod is at x' = (40 cm + 16.00 cm + 12.00 cm)/2 = 70.00 cm/2 = 35 cm

The distance between the center of the rod and the center of gravity is x' - x = 35 cm - 33.14 cm = 1.86 cm

So, the center of gravity is 1.86 cm away from the center of the rod and closer to the 0.700 kg sphere.

5 0

3 years ago