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Nadusha1986 [10]
3 years ago
10

Help mee plss its very urgent i need this before 11 pm est

Physics
2 answers:
dmitriy555 [2]3 years ago
6 0

Answer:

7. 2 kg

8. 0.5 kg

9. 4 kg

Explanation:

The equation is F=MA

where F is force in Newtons

M is mass in kg

A is acceleration in m/s^2

for each you substitute in the F and A, and you are finding M. Meaning you divide F by A.

M = F/A

6/3 = 2

6/12 = 0.5

20/5 = 4

Vera_Pavlovna [14]3 years ago
5 0

Answer:

Explanation:

m = 2 kg

m = 0.5 kg

m = 4 kg

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<h3>Calculating Magnetic field strength & Energy density </h3>

From the question, we are to find the magnetic field strength

The magnetic field strength of a loop can be calculated by using the formula,

B = \frac{\mu_{0} I}{2R}

Where  B is the magnetic field strength

\mu_{0} is the permeability of free space (\mu_{0}=4\pi \times 10^{-7} \ N/A^{2})

I is the current

and R is the radius

From the give information,

R = 75 \ mm= 75 \times 10^{-3} \ m

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B = \frac{4\pi \times 10^{-7} \times 113}{2 \times 75 \times 10^{-3} }

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Hence, the magnetic field strength is 9.47 ×10⁻⁴ T

Now, for the energy density

Energy density can be calculated by using the formula,

u_{B}  = \frac{B^{2} }{2\mu_{0} }

Where u_{B} is the energy density

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u_{B}= \frac{(9.47\times 10^{-4} )^{2} }{2 \times 4\pi \times 10^{-7} }

u_{B} = 0.36 \ J/m^{3}

Hence, the energy density at the center of the loop is 0.36 J/m³

Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557

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