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3 years ago

12

(100 POINTS!!) Short answer about how acceleration is dependent on the speed and direction of an object!!!! please help!!!!!

2 answers:

zhuklara [117]3 years ago

8 0

Answer:

The acceleration of the object is dependent upon this velocity change and is in the same direction as this velocity change. The acceleration of the object is in the same direction as the velocity change vector; the acceleration is directed towards point C as well - the center of the circle.

i hope that helped you!!

Explanation:

natka813 [3]3 years ago

7 0

Answer:

acceleration = velocity/time m/s²

Explanation:

speed could replace velocity in the equation I offered above

please mark brainliest

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If an object in motion, experiences a net zero unbalanced force, the the body

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Answer:

4) moves with constant velocity

Explanation:

If an object is in motion, three things can happen:

1. The object slows down in speed.

This means a net force is needed to be able to slow the object down in speed.

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3. The object remains in motion at the same speed.

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This is the given situation. So this is the right answer.

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3 years ago

Can we see the back side of the moon from earth?

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A biker pedals hard for 3 seconds. What is his initial velocity if he accelerated by 4m/s2 until he's going 20m/s. (Which equati

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Answer:

answer is option 4

Explanation:

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3 years ago

A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o

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a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

$\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s$

The linear speed of the sock is given by

$v=\omega r$

where

$\omega$ is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

$v=(3.14)(0.50)=1.57 m/s$

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

$r' = 2r = 1.00 m$

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

$\omega' = \omega = 3.14 rad/s$

Therefore, the new linear speed would be:

$v'=\omega' r' = \omega (2r)$

And substituting,

$v'=(3.14)(1.00)=3.14 rad/s = 2v$

So, we see that the linear speed has doubled.

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3 years ago