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sladkih [1.3K]
4 years ago
15

While John is traveling along an interstate highway, he notices a 150 mi marker as he passes through town. Later John passes a 1

12 mi marker. What is the distance between town and John’s current location? Answer in units of mi. 003 (part 2 of 2) 10.0 points What is John’s current position?
Physics
2 answers:
Lerok [7]4 years ago
7 0

Answer:

Part a)

distance = 112 miles

Part b)

current position = 112 miles from the position of town

Explanation:

Part a)

Since the distance marker is showing the distance between the town and the position of john at all time

so here we have

d = 112 miles

Part b)

Current position of John is given as

r = 112 miles

from the position of the town

lisov135 [29]4 years ago
7 0

Answer:

a) When John is in the town (and suppose that he is travelling in a straigth line), he sees a 150 mi marker (means that he is 150 mi away from somewhere, let's suppose is a city), and latter, he sees a 112 mi marker (so he is now 112mi from the city) this means that he is closer to the city, and further to the town, then, the distance between john and the town will be 150 mi - 112 mi = 38 mi

b) currently, john is 38 mi ahead of the town and 112 mi away from the city.

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nydimaria [60]

Answer:

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Explanation:

Given that,

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Put the value into the formula

I=\dfrac{1}{2}\times475\times(1.50)^2

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K.E=\dfrac{1}{2}I\omega^2

Put the value into the formula

K.E = \dfrac{1}{2}\times534.375\times(4000\times\dfrac{2\pi}{60})^2

K.E=46880620.9\ J

K.E =46.88\times10^{6}\ J

K.E =46.88\ MJ

(b). We need to calculate the length of time the car could run before the flywheel  would have to be brought backup to speed

Using formula of time

t=\dfrac{46.88\times10^{6}}{11190}

t=4189.45\ sec

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3 0
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vazorg [7]

Answer:

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Explanation:

From the question we are told that

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substituting values

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The negative sign show that the CD is decelerating  but the magnitude is

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3 years ago
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sergey [27]

Answer:

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5 0
3 years ago
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tatuchka [14]

<u>Given that:</u>

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