Hi there!
Recall the equation for electric potential of a point charge:
V = Electric potential (V)
k = Coulomb's Constant(Nm²/C²)
Q = Charge (C)
r = distance (m)
We can begin by solving for the given electric potentials. Remember, charge must be accounted for. Electric potential is also a SCALAR quantity.
Upper right charge's potential:
Lower left charge's potential:
Add the two, and subtract from the total EP at the point:
The remaining charge must have a potential of 2036.25 V, so:
Answer:
Explanation:
Note that acceleration is the rate change of velocity i.e
.
Since the velocity is giving as a variable dependent on the pressure, we have to differentiate implicitly both side with respect to time,i.e
if we substitute value for the pressure as giving in the question and also since the rate change of pressure is 0.354psi/sec, we have
Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.
Explanation:
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