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Elena L [17]
3 years ago
5

A solid must be given​

Physics
1 answer:
alexdok [17]3 years ago
8 0
I- what....? Lolllll
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An elevator weighs 1500 Newtons. Calculate how much potential energy it has when it is lived 500 meters in the air.
avanturin [10]

An elevator has 750,000 J when it is lived 500 meters in the air

Answer: Option D

<u>Explanation:</u>

The expression to find the potential energy completely on the basis of forces that on two objects. It can be written as

potential\ energy (P . E)=m \times acceleration\ due\ to\ gravity\ (g) \times height (h)

Where,

m – mass of object

Acceleration due to gravity =  9.8 \mathrm{m} / \mathrm{s}^{2}

h = 500 meters

Force = 1500 Newton

As we know, according to Newton second law of motion, the force can be expressed in terms of mass and gravity (F= ma). So, the potential energy can be calculated as

P . E=F \times h=1500(500)=750000 J

Hence, an elevator has 750,000 J when it is lived 500 meters in the air.

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3 years ago
Which of the following is true about a family psychologist?
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Which list places the layers of the sun in the correct order from outermost to innermost?
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Answer - corona, chromosphere, photosphere
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Three identical resistors are connected in parallel. The equivalent resistance increases by 630 when one resistor is removed and
strojnjashka [21]

Answer:

each resistor is 540 Ω

Explanation:

Let's assign the letter R to the resistance of the three resistors involved in this problem. So, to start with, the three resistors are placed in parallel, which results in an equivalent resistance R_e defined by the formula:

\frac{1}{R_e}=\frac{1}{R} } +\frac{1}{R} } +\frac{1}{R} \\\frac{1}{R_e}=\frac{3}{R} \\R_e=\frac{R}{3}

Therefore, R/3 is the equivalent resistance of the initial circuit.

In the second circuit, two of the resistors are in parallel, so they are equivalent to:

\frac{1}{R'_e}=\frac{1}{R} +\frac{1}{R}\\\frac{1}{R'_e}=\frac{2}{R} \\R'_e=\frac{R}{2} \\

and when this is combined with the third resistor in series, the equivalent resistance (R''_e) of this new circuit becomes the addition of the above calculated resistance plus the resistor R (because these are connected in series):

R''_e=R'_e+R\\R''_e=\frac{R}{2} +R\\R''_e=\frac{3R}{2}

The problem states that the difference between the equivalent resistances in both circuits is given by:

R''_e=R_e+630 \,\Omega

so, we can replace our found values for the equivalent resistors (which are both in terms of R) and solve for R in this last equation:

\frac{3R}{2} =\frac{R}{3} +630\,\Omega\\\frac{3R}{2} -\frac{R}{3} = 630\,\Omega\\\frac{7R}{6} = 630\,\Omega\\\\R=\frac{6}{7} *630\,\Omega\\R=540\,\Omega

8 0
3 years ago
A weight lifter does 586 J of work on a weight that he lifts in 3.5 seconds. What is the power with which he lifts the weight?
Neko [114]

Answer:

Explanation:

The quantity of energy transferred by a force when it is applied to a body and causes that body to move in the direction of the force work.

7 0
2 years ago
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