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1 year ago

Two planets X and Y travel counterclockwise in circular orbits about a star, as seen in the figure.

Physics

1 answer:

sergeinik [125]1 year ago

8 0

Planet Y has rotated by 135.5° through during this time.

To find the answer, we need to know about the relation between angle and radius of orbit.

<h3>What's the expression of angle in terms of radius?</h3>

Angle= arc/radius
As arc = orbital velocity × time,

angle= (orbital velocity × time)/radius

Orbital velocity= √(GM/radius), G= gravitational constant and M = mass of sun
So, angle = (√(GM)× time)/radius^3/2

<h3>What's is the angle rotated by planet Y after 5 years, if ratio of the radius of orbit of planet X and Y is 4:3 and planet X is rotated by 88°?</h3>

Let Ф₁= angle rotated by planet Y, Ф₂= angle rotated by planet X
As time = 5 years ( a constant)
Ф₁/Ф₂= (radius of planet X / radius of planet Y)^(3/2)
Ф₁= (radius of planet X / radius of planet Y)^(3/2) × Ф₂

= (4/3)^(3/2) × 88°

= 135.5°

Thus, we can conclude that Planet Y has rotated by 135.5° through during this time.

Learn more about the orbital velocity here:

brainly.com/question/22247460

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What is the difference between brake horsepower and thrust horsepower?

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1. HP is the output horsepower rating of an engine, while Brake horse power is the input brake horsepower of an engine. ... Brake horse power is the measurement of an engine's power without any power losses, while HP is less the power losses Brake horse power

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3 years ago

(TCO 5) The relationship between Celsius (º C) and Fahrenheit (º F) degree of measuring temperature is linear. Find the linear e

gtnhenbr [62]

Answer:

$C=-\dfrac{10}{17}(F-32)$

Explanation:

Given that

32° F corresponds to 0 °C. ---Point 1

212° F corresponds to 100 °C.----Point 2

We know that if two point is given that equation of line can be found as

$y-y_1=\dfrac{y_2-y_1}{x_2-x_2}(x-x_1)$

Lets C in y- direction and F in x- direction,so we can say that

$C-C_1=\dfrac{C_2-C_1}{F_2-F_2}(F-F_1)$

$C-0=\dfrac{100-0}{32-212}(F-32)$

$C=-\dfrac{10}{17}(F-32)$

So the linear relationship is

$C=-\dfrac{10}{17}(F-32)$

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3 years ago

What is the term for a motion you make on a touch screen with the tip of one or more fingers or your hand?

frozen [14]

Double tap, zoom in.

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3 years ago

A bicycle has wheels of 0.8 m diameter. The bicyclist accelerates from rest with constant acceleration to 22 km/h in 11.6 s. Wha

larisa [96]

Answer:

α = 1.32 rad/s²

Explanation:

given,

diameter of the bicycle = 0.8 m

radius of the bicycle = 0.4 m

initial speed of the bicyclist,u = 0 m/s

final speed of the bicyclist,v = 22 Km/h = 22 x 0.278

= 6.12 m/s

time,t = 11.6 s

acceleration = $\dfrac{v-u}{t}$

= $\dfrac{6.12-0}{11.6}$

=0.53 m/s²

we know,

a = α r

$\alpha=\dfrac{a}{r}$

$\alpha=\dfrac{0.53}{0.4}$

α = 1.32 rad/s²

the angular acceleration of the wheels is equal to α = 1.32 rad/s²

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3 years ago

Activity Problem 8.3 This problem asks you to compare the finite current element approximation to the infinite straight wire app

Tresset [83]

Answer: (a) B = 2 x 10⁻⁵T

(b) B = 1.94 x 10⁻⁵T

Explanation: A magnetic field due to a current passing through a straight wire is calculated using the <u>Biot-Savart</u> <u>Law</u>:

$dB=\frac{\mu_{0}}{4.\pi} \frac{IdLXR}{r^{3}}$

where

dL is current length element

$\mu_{0}$ is permeability of free space ( $4.\pi.10^{-7}$ T.m/A)

(a) For a infinite straight wire:

$B=\frac{\mu_{0}I}{2.\pi.R}$

$B=\frac{4.\pi.10^{-7}.2}{2.\pi.2.10^{-2}}$

B = 2x10⁻⁵T

For an infinite, long and straight wire, magnetic field is 2x10⁻⁵T.

(b) For a finite wire:

$B=\frac{\mu_{0}I}{2.\pi.R}\frac{L}{\sqrt{L^{2}+R^{2}} }$

$B=\frac{4.\pi.10^{-7}.2}{2.\pi.2.10^{-2}} \frac{8.10^{-2}}{\sqrt{(8.10^{-2})^{2}+(2.10^{-2})^{2}} }$

B = 1.94x10⁻⁵T

The magnetic field for a finite wire in the same conditionsas infinite wire is 1.94x10⁻⁵T.

$B=\frac{\mu_{0}I}{4.\pi.L\sqrt{2} }$

$B=\frac{4.\pi.10^{-7}.2}{4.\pi.8.10^{-2}\sqrt{2} }$

B = 0.18x10⁻⁵T

At a point at the end, magnetic field is 1.8x10⁻⁴T.

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3 years ago