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4 years ago

How many atoms of hydrogen are in ethanol (C2H5OH)?

1 answer:

6 0

So we have: 1 C2H5OH + _ O2 -> 2 CO2 + _ H2O Step 3: The only molecule on the right that is left is H2O. We start with 6 hydrogen atoms on the left.

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The science of the creation of maps and charts is called

Kay [80]

The answer is Cartography.

5 0

3 years ago

Under conditions of constant temperature and amount of substance, a plot of pressure VS. volume for an ideal gas will result in:

Minchanka [31]

Answer:

d) none of the above

Explanation:

The law that describes the relationship between pressure and volume of an ideal gas (under constant temperature and amount of substance) is Boyle's law.

It states that pressure is inversely proportional to the volume. This would mean that a graph of P vs 1/V would be a line.

See the attached picture for a graph of P vs V.

4 0

3 years ago

2Ag (s) + H2S(s) → Ag2S(s) + H2(g)

Advocard [28]

Answer: Oxidation half: $2Ag\rightarrow 2Ag^++2e^-$

Reduction half: $2H^++2e^-\rightarrow H_2$

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

$2Ag(s)+H_2S(s)\rightarrow Ag_2S(s)+H_2(g)$

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

Oxidation half: $2Ag\rightarrow 2Ag^++2e^-$

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

Reduction half: $2H^++2e^-\rightarrow H_2$

8 0

3 years ago

What are 2 examples of ethical research behaviour?

FromTheMoon [43]

Answer:

Respect
Confidentiality

Explanation:

*Hope this helps*

6 0

3 years ago

What volume of nitrogen gas at STP would react with 37.2 g of magnesium to produce magnesium nitride

anastassius [24]

Answer:

11.58 L of N₂

Explanation:

We'll begin by calculating the number of mole in 37.2 g of magnesium. This can be obtained as follow:

Mass of Mg = 37.2 g

Molar mass of Mg = 24 g/mol

Mole of Mg =?

Mole = mass /Molar mass

Mole of Mg = 37.2 / 24

Mole of Mg = 1.55 moles

Next, we shall write the balanced equation for the reaction. This is illustrated below:

3Mg + N₂ —> Mg₃N₂

From the balanced equation above,

3 moles of Mg reacted with 1 mole of N₂.

Therefore, 1.55 moles of Mg will react with = (1.55 × 1)/3 = 0.517 mole of N₂

Thus, 0.517 mole of N₂ is need for the reaction.

Finally, we shall determine the volume of N₂ needed for the reaction as follow:

Recall:

1 mole of a gas occupies 22.4 L at STP.

1 mole of N₂ occupied 22.4 L at STP.

Therefore, 0.517 mole of N₂ will occupy = 0.517 × 22.4 = 11.58 L at STP

Thus, 11.58 L of N₂ is needed for the reaction.

6 0

3 years ago