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lisov135 [29]
3 years ago
7

How many atoms of hydrogen are in ethanol (C2H5OH)?

Chemistry
1 answer:
EleoNora [17]3 years ago
6 0
So we have: 1 C2H5OH + _ O2 -> 2 CO2 + _ H2O Step 3: The only molecule on the right that is left is H2O. We start with 6 hydrogen atoms<span> on the left.</span>
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What is the empirical formula of a substance that contains 8.33×10−2 mol of carbon, 0.167 mol of hydrogen, and 8.32×10−2 mol of
Olegator [25]
Looks to me like C and O are virtually equal and H is double those, so:

CH_20, which is the empirical formula for carbohydrates.
6 0
3 years ago
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What structure do bacteria cells have
g100num [7]

Answer:

They are clumped together and fluffy looking

Explanation:

I’ve seen what they looked like in a project during highschool we swabbed some books and door handles and saw which had the most bacteria. It was surprisingly the books

6 0
1 year ago
Please help me thank you :)
LenaWriter [7]

Answer:

D. 3220

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3 years ago
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The electron cloud of HF is smaller than that of F2, however, HF has a much higher boiling point than F2 has. Which of the follo
mafiozo [28]

Answer:D

Explanation:

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7 0
2 years ago
Given: logK=nE∘0.0592 What is the value K for this redox reaction? Zn2+(aq) + 2 Cl−(aq) → Zn(s) + Cl2(
anygoal [31]

<em>K</em> = 2.4 × 10^(-72)

<em>Step 1</em>. Determine the <em>value of n </em>

Zn^(2+) + 2e^(-) → Zn

2Cl^(-) → Cl_2 + 2e^(-)

Zn^(2+) + 2Cl^(-) → Zn + Cl_2

∴ <em>n</em> = 2

<em>Step 2</em>. Calculate <em>K</em>

log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62

<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)

8 0
3 years ago
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