Explanation:
Given parameters:
Number of moles of the sulfur trioxide = 1.55kmol = 1.55 x 10³mole
Unknown:
Mass of the sulfur trioxide = ?
Solution:
To solve for the mass of the sample of sulfur trioxide:
- Find the molar mass of the compound i.e SO₃
atomic mass of S = 32g
O = 16g
molar mass = 32 + 3(16) = 80g/mol
mass of SO₃ = number of moles x molar mass
mass of SO₃ = 1.55 x 10³ x 80 = 124000g or 124kg
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mole calculation brainly.com/question/13064292
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Answer:
11.55 mol ≈ 11.6 mol CO2
Explanation:
C3H8 (g) + 5O2(g) → 3CO2 (g) + 4H2O(g)
from reaction 1 mol 3 mol
given 3.85 mol x mol
Solving proportion
x =(3.85*3)/1 = 11.55 mol ≈11.6 mol
Answer:
There are 8 electrons in the last level. Because of the octet rule.
