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Anettt [7]
3 years ago
8

Which mineral group is composed of compounds that contain atoms of sulfur and one or more metals?

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

The answer to your questions is: C. Sulfides

Explanation:

A. Phosphates  these compounds do not have sulphur, they are composed by phosphate and oxygen, So this answer is wrong.

B. Sulfates  are formed by sulphur and oxygen, not for a metal, then this is not the right answer.

C. Sulfides  are molecules formed by a metal and sulphur, this is the anwser to the question.

D. Silicates are formed by sillicon and oxygen, this option is incorrect.

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Solid-solid homogeneous mixture give one example
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Example of solid - solid homogeneous mixture is copper metal - silver metal like coins and alloys. Homogeneous mixture is a mixture in which one of the substances often changes in form as in a solution of sugar in water. It contains variable proportions. Solution can contain two substances, three substances or more, in a single physical state. The component of a solution that is present in greatest quantity is usually called the solvent and all other components are called solutes.
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3 years ago
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What 3 classes of compounds are elecrolytes
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Answer:

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3 years ago
Which of these statements are not true about a chemical reaction rate?
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A) Temperature does not affect reaction rate
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3 years ago
Select the correct answer. Which statement is true for a heating curve?
Anon25 [30]

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OB

Explanation:

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8 0
3 years ago
A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C
Mamont248 [21]

Answer:

T_{eq}=23.85^oC

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

\Delta H_{Cu}=-\Delta H_{H_2O}

Therefore the equilibrium temperature shows up as:

m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC

Best regards.

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