6x + 4y = -24
30x + 20y = -120
You can multiply all of the numbers by any common factor and get an equation that works.
Answer+Step-by-step explanation:
![f^{-1}\left( x\right) =\frac{1}{7} x^{2}+3 \ ,\text{where}\ x\geq 0](https://tex.z-dn.net/?f=f%5E%7B-1%7D%5Cleft%28%20x%5Cright%29%20%20%3D%5Cfrac%7B1%7D%7B7%7D%20x%5E%7B2%7D%2B3%20%5C%20%2C%5Ctext%7Bwhere%7D%5C%20x%5Cgeq%200)
![5\cdot(\frac{1}{5^3})\ne5\cdot(5^3)](https://tex.z-dn.net/?f=5%5Ccdot%28%5Cfrac%7B1%7D%7B5%5E3%7D%29%5Cne5%5Ccdot%285%5E3%29)
His answer is not correct, when we have a power on the denominator it is dividing and not multiplying, in this case while the expression on the left is being divided the other one is multiplying.
also you could rewrite the expressions like so remembering that powers that are on the denominator can be written as negative powers.
I’m pretty sure 2 and 5/7 as an improper fraction is 19 but I’m not sure since on your question it doesn’t show 19 as an answer.
Answer:
I don't have a clue
Step-by-step explanation: